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Groups > gnu.bash.bug > #11342

declare -f produces non eval'able output

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From isabella parakiss <izaberina@gmail.com>
Newsgroups gnu.bash.bug
Subject declare -f produces non eval'able output
Date Thu, 13 Aug 2015 18:06:44 +0200
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declare -f doesn't know that most keywords are valid function names:

$ function time () { :; }
$ declare -f time
time () 
{ 
    :
}

It should probably check if the name is if/for/time... before printing it.


---
xoxo iza

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declare -f produces non eval'able output isabella parakiss <izaberina@gmail.com> - 2015-08-13 18:06 +0200

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