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| From | hk <hkadeveloper@gmail.com> |
| Newsgroups | gnu.bash.bug |
| Subject | shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression? |
| Date | Wed, 2 Oct 2019 08:35:30 +0800 |
| Lines | 14 |
| Approved | bug-bash@gnu.org |
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Configuration Information : Bash Version: 5.0 Patch Level: 0 Release Status: release Description: the code snippet from expr.c starting from line 141: > /* This should be the function corresponding to the operator with the > highest precedence. */ > #define EXP_HIGHEST expcomma Am I understanding it wrong or is it a typo?
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shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression? hk <hkadeveloper@gmail.com> - 2019-10-02 08:35 +0800
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