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Groups > gnu.bash.bug > #15448 > unrolled thread

shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression?

Started byhk <hkadeveloper@gmail.com>
First post2019-10-02 08:35 +0800
Last post2019-10-02 08:35 +0800
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  shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression? hk <hkadeveloper@gmail.com> - 2019-10-02 08:35 +0800

#15448 — shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression?

Fromhk <hkadeveloper@gmail.com>
Date2019-10-02 08:35 +0800
Subjectshouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression?
Message-ID<mailman.707.1569976552.2651.bug-bash@gnu.org>
Configuration Information :
Bash Version: 5.0
Patch Level: 0
Release Status: release

Description:
the code snippet from expr.c starting from line 141:

> /* This should be the function corresponding to the operator with the
>    highest precedence. */
> #define EXP_HIGHEST expcomma


Am I understanding it wrong or is it a typo?

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