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Groups > gnu.bash.bug > #16760
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|---|---|
| From | Eric Blake <eblake@redhat.com> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: echo builtin doesn't handle end-of-options flag |
| Date | Sun, 16 Aug 2020 11:30:59 -0500 |
| Organization | Red Hat, Inc. |
| Lines | 29 |
| Approved | bug-bash@gnu.org |
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| To | Eli Schwartz <eschwartz@archlinux.org>, bug-bash@gnu.org |
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On 8/16/20 11:20 AM, Eli Schwartz wrote: > https://pubs.opengroup.org/onlinepubs/9699919799/utilities/echo.html > > echo does not accept options, and is not permitted to accept options > including "--". > > bash does accept -n, -e, -E in violation of POSIX, unless shopt -s shopt > -s xpg_echo is set, but it doesn't implement -- and I don't really see a > justification to do so. Not quite: https://www.austingroupbugs.net/view.php?id=1222 says that accepting -e and -E will become acceptable in the next revision of POSIX (accepting -n was already acceptable on non-XSI systems). > Either enable xpg_echo or use printf. POSIX recommends using printf. My personal recommendation is to avoid xpg_echo except when trying to break things - there are a number of what claim to be bash scripts that are not aware of the effects of xpg_echo and which operate incorrectly when you actually set it; whereas using printf is reliably portable. -- Eric Blake, Principal Software Engineer Red Hat, Inc. +1-919-301-3226 Virtualization: qemu.org | libvirt.org
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Re: echo builtin doesn't handle end-of-options flag Eric Blake <eblake@redhat.com> - 2020-08-16 11:30 -0500
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