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Re: echo builtin doesn't handle end-of-options flag

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On Aug 16, 2020, at 12:21 PM, Eric Blake <eblake@redhat.com> wrote:

> I see nothing in your report about bash disobeying POSIX, but rather confusion on your part about what POSIX actually requires.

I didn't say it violated POSIX. My expectations were set by the Bash Manual, which describes the behavior I'm expecting in the Shell Builtin Commands section:

> Unless otherwise noted, each builtin command documented as accepting options preceded by ‘-’ accepts ‘--’ to signify the end of the options.

To be fair, the documentation later calls out that "echo does not interpret -- to mean the end of options", but this wasn't obvious on first reading. If the demonstrated behavior is correct and/or desirable, then it's not a bug. I still found it surprising, but I'm honestly not sure how to improve the documentation to draw more attention to the known behavior. Maybe it could be bolded, or listed as a caveat, because it's easy to overlook. 

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Re: echo builtin doesn't handle end-of-options flag "Todd A. Jacobs" <tjacobs@codegnome.com> - 2020-08-16 12:42 -0400

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