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Groups > gnu.bash.bug > #14257
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| From | Martijn Dekker <martijn@inlv.org> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: $OPTIND varibale value is different from sh |
| Date | Wed, 20 Jun 2018 19:09:09 +0100 |
| Lines | 20 |
| Approved | bug-bash@gnu.org |
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Op 20-06-18 om 13:39 schreef Greg Wooledge: > I really don't understand what you're doing here, either. The only > use of OPTIND is after the final call to getopts, when there are no > more options to process. At that point, OPTIND tells you how many > times you have to "shift" to get rid of all the options that were > processed. (And you have to subtract 1, because legacy historical > reasons.) In other words, because all the options have now been processed, OPTIND points to the first argument *after* the list of options. I don't see how that is "because legacy historical reasons". It seems both logical and useful to me. > Any attempt to use OPTIND in the middle of the loop seems pointless > and hazardous to me. Agreed. - M.
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Re: $OPTIND varibale value is different from sh Martijn Dekker <martijn@inlv.org> - 2018-06-20 19:09 +0100
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