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| From | Daniel Krügler <daniel.kruegler@googlemail.com> |
|---|---|
| Newsgroups | comp.std.c++ |
| Subject | Re: Proposal: constexpr, non-const member functions |
| Date | 2011-11-08 14:47 -0800 |
| Organization | A noiseless patient Spider |
| Message-ID | <j9c7tk$n8j$1@dont-email.me> (permalink) |
| References | <46713.10.0.7.178.1320718071.squirrel@webmail.secure.aluminati.net> |
Am 08.11.2011 20:32, schrieb Richard Smith:
>
> Hi,
>
> Pointers and references to non-const objects can generally be used within
> constant expressions in C++11. However, there is a roadblock in the way of
> anyone who wants to use them as the 'this' pointer, because constexpr member
> functions are implicitly const. Consider a trivial class like this:
>
> template<typename T>
> class Wrapper {
> T v;
> public:
> constexpr Wrapper(const T&v) : v(v) {}
> T&get() { return v; } // note, can't be constexpr
> constexpr const T&get() { return v; }
> // ...
> };
>
> This seems fine until you try to use a temporary of this type in a constant
> expression:
>
> constexpr int n = Wrapper<int>(0).get(); // ill-formed!
>
> This doesn't work, because the non-const (and thus non-constexpr) get()
> overload is selected.
>
> Since C++11 is already out of the gate, it's too late to remove the 'constexpr
> implies const' rule, so instead we could consider a syntax like this:
>
> constexpr T&get() mutable { return v; }
>
> Does this seem like a useful extension?
I completely agree with your analysis, I have the exactly same
impression of the status quo and of their inconsistencies. I
originally became aware of it by looking at the two basic kinds of
constant expressions, namely "value"-based ones (especially
rvalue-based), where a constant member function is the natural
solution for it, and "identity"-constant expressions (like
address-constant or reference-constant expressions), where both
constant and non-constant member functions are useful. It makes sense
to allow for a reference-constant expression even for non-const member
functions (or objects), because we can still have references (or
pointers) to non-const objects.
I tend to say that a good long-term suggestion would be to extend
mutable for member functions as you describe - the good news are that
lambda expressions already use this approach, so its not completely
new. My current short-term approach is to use free constexpr functions
as a workaround wherever possible. This is probably not the worst idea
as a general principle anyway, but enforcing it is actual against the
spirit of C++ and does not work for all functions (because some are
required to be member functions).
Greetings from Bremen,
Daniel Krügler
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Back to comp.std.c++ | Previous | Next — Previous in thread | Next in thread | Find similar
Proposal: constexpr, non-const member functions "Richard Smith"<richard@metafoo.co.uk> - 2011-11-08 11:32 -0800
Re: Proposal: constexpr, non-const member functions Dave Abrahams <dave@boostpro.com> - 2011-11-08 14:45 -0800
Re: Proposal: constexpr, non-const member functions Daniel Krügler <daniel.kruegler@googlemail.com> - 2011-11-08 14:47 -0800
Re: Proposal: constexpr, non-const member functions Marc <marc.glisse@gmail.com> - 2011-11-08 14:47 -0800
Re: Proposal: constexpr, non-const member functions Daniel Krügler <daniel.kruegler@googlemail.com> - 2011-11-09 21:54 -0800
Re: Proposal: constexpr, non-const member functions Daniel Krügler<daniel.kruegler@googlemail.com> - 2011-11-09 23:14 -0800
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