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| Started by | Chris Angelico <rosuav@gmail.com> |
|---|---|
| First post | 2016-04-09 00:08 +1000 |
| Last post | 2016-04-09 00:08 +1000 |
| Articles | 1 — 1 participant |
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Re: how to convert code that uses cmp to python3 Chris Angelico <rosuav@gmail.com> - 2016-04-09 00:08 +1000
| From | Chris Angelico <rosuav@gmail.com> |
|---|---|
| Date | 2016-04-09 00:08 +1000 |
| Subject | Re: how to convert code that uses cmp to python3 |
| Message-ID | <mailman.84.1460124521.2253.python-list@python.org> |
On Fri, Apr 8, 2016 at 11:31 PM, Antoon Pardon <antoon.pardon@rece.vub.ac.be> wrote: > Doing it as follows: > seq1 < seq2 > seq2 < seq1 > > takes about 110 seconds. > > > Doing it like this: > delta = cmp(seq1, seq2) > delta < 0 > delta > 0 > > takes about 50 seconds. Why are you comparing in both directions, though? cmp() is more equivalent to this: seq1 == seq2 seq1 < seq2 You only need ONE comparison, and the other is presumed to be its opposite. When, in the Python 3 version, would you need to compare twice? ChrisA
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