Re: how to convert code that uses cmp to python3

From	Chris Angelico <rosuav@gmail.com>
Newsgroups	comp.lang.python
Subject	Re: how to convert code that uses cmp to python3
Date	2016-04-09 00:08 +1000
Message-ID	<mailman.84.1460124521.2253.python-list@python.org> (permalink)
References	(3 earlier) <CAPTjJmrbL870mV1kU8nHar=bPyKZRmhKP-8iUs_tpYVo5vhhOA@mail.gmail.com> <57075F43.7060004@rece.vub.ac.be> <85fuuw5ypl.fsf@benfinney.id.au> <5707B2CE.1010407@rece.vub.ac.be> <CAPTjJmrMv5O5vwrbfHJJCdiHi87naPOanhPmk4Ba_SLRgu1m4Q@mail.gmail.com>

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On Fri, Apr 8, 2016 at 11:31 PM, Antoon Pardon
<antoon.pardon@rece.vub.ac.be> wrote:
> Doing it as follows:
>     seq1 < seq2
>     seq2 < seq1
>
> takes about 110 seconds.
>
>
> Doing it like this:
>     delta = cmp(seq1, seq2)
>     delta < 0
>     delta > 0
>
> takes about 50 seconds.

Why are you comparing in both directions, though? cmp() is more
equivalent to this:

seq1 == seq2
seq1 < seq2

You only need ONE comparison, and the other is presumed to be its
opposite. When, in the Python 3 version, would you need to compare
twice?

ChrisA

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Re: how to convert code that uses cmp to python3 Chris Angelico <rosuav@gmail.com> - 2016-04-09 00:08 +1000

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