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fast dictionary initialization

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  fast dictionary initialization maurice <mauricioliveiraguarda@gmail.com> - 2016-06-10 14:07 -0700
    Re: fast dictionary initialization Random832 <random832@fastmail.com> - 2016-06-10 17:15 -0400
    Re: fast dictionary initialization Tim Chase <python.list@tim.thechases.com> - 2016-06-10 18:20 -0500

#109798 — fast dictionary initialization

Hi. If I have already a list of values, let's call it valuesList and the keysList, both same sized lists, what is the easiest/quickest way to initialize a dictionary with those keys and list, in terms of number of lines perhaps?

example:
valuesList = [1,2,3]
keysList   = ['1','2','3']

So the dictionary can basically convert string to int:

dictionary = {'1':1, '2':2, '3':3}

Thanks

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#109799

pOn Fri, Jun 10, 2016, at 17:07, maurice wrote:
> Hi. If I have already a list of values, let's call it valuesList and the
> keysList, both same sized lists, what is the easiest/quickest way to
> initialize a dictionary with those keys and list, in terms of number of
> lines perhaps?
> 
> example:
> valuesList = [1,2,3]
> keysList   = ['1','2','3']
> 
> So the dictionary can basically convert string to int:
> 
> dictionary = {'1':1, '2':2, '3':3}

dict(zip(keysList, valuesList))

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#109811

On 2016-06-10 14:07, maurice wrote:
> example:
> valuesList = [1,2,3]
> keysList   = ['1','2','3']
> 
> So the dictionary can basically convert string to int:
> 
> dictionary = {'1':1, '2':2, '3':3}

A couple similar options:


The most straightforward translation of your description:

  opt1 = dict(zip(keysList, valuesList))
  print(opt1["2"])

And one where you generate the strings on the fly:

  opt2 = dict((str(i), i) for i in range(1, 4))
  print(opt2["2"])

And one where you use the int() function instead of a mapping because
the whole idea of storing a dict worth of string-numbers-to-numbers
seems somewhat silly to me:

  print(int("2"))

-tkc

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