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Groups > comp.lang.python > #26625 > unrolled thread
| Started by | Tom P <werotizy@freent.dd> |
|---|---|
| First post | 2012-08-06 17:52 +0200 |
| Last post | 2012-08-06 21:14 +0100 |
| Articles | 3 on this page of 23 — 13 participants |
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looking for a neat solution to a nested loop problem Tom P <werotizy@freent.dd> - 2012-08-06 17:52 +0200
Re: looking for a neat solution to a nested loop problem John Gordon <gordon@panix.com> - 2012-08-06 16:03 +0000
Re: looking for a neat solution to a nested loop problem Tom P <werotizy@freent.dd> - 2012-08-06 19:16 +0200
Re: looking for a neat solution to a nested loop problem Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2012-08-07 01:27 +0000
Re: looking for a neat solution to a nested loop problem Ian Foote <ian@feete.org> - 2012-08-06 17:07 +0100
Re: looking for a neat solution to a nested loop problem Ethan Furman <ethan@stoneleaf.us> - 2012-08-06 09:15 -0700
Re: looking for a neat solution to a nested loop problem Nobody <nobody@nowhere.com> - 2012-08-06 17:18 +0100
Re: looking for a neat solution to a nested loop problem Tom P <werotizy@freent.dd> - 2012-08-06 19:14 +0200
Re: looking for a neat solution to a nested loop problem Emile van Sebille <emile@fenx.com> - 2012-08-06 11:11 -0700
Re: looking for a neat solution to a nested loop problem Larry Hudson <orgnut@yahoo.com> - 2012-08-06 21:02 -0700
Re: looking for a neat solution to a nested loop problem Nobody <nobody@nowhere.com> - 2012-08-07 16:32 +0100
Re: looking for a neat solution to a nested loop problem 88888 Dihedral <dihedral88888@googlemail.com> - 2012-08-07 18:42 -0700
Re: looking for a neat solution to a nested loop problem 88888 Dihedral <dihedral88888@googlemail.com> - 2012-08-09 11:46 -0700
Re: looking for a neat solution to a nested loop problem 88888 Dihedral <dihedral88888@googlemail.com> - 2012-08-09 11:39 -0700
Re: looking for a neat solution to a nested loop problem 88888 Dihedral <dihedral88888@googlemail.com> - 2012-08-14 14:08 -0700
Re: looking for a neat solution to a nested loop problem Grant Edwards <invalid@invalid.invalid> - 2012-08-06 18:25 +0000
Re: looking for a neat solution to a nested loop problem Grant Edwards <invalid@invalid.invalid> - 2012-08-06 18:29 +0000
Re: looking for a neat solution to a nested loop problem Tom P <werotizy@freent.dd> - 2012-08-06 21:03 +0200
Re: looking for a neat solution to a nested loop problem Grant Edwards <invalid@invalid.invalid> - 2012-08-06 19:22 +0000
Re: looking for a neat solution to a nested loop problem Emile van Sebille <emile@fenx.com> - 2012-08-06 12:52 -0700
Re: looking for a neat solution to a nested loop problem André Malo <ndparker@gmail.com> - 2012-08-06 20:19 +0200
Re: looking for a neat solution to a nested loop problem Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2012-08-06 15:31 -0400
Re: looking for a neat solution to a nested loop problem Arnaud Delobelle <arnodel@gmail.com> - 2012-08-06 21:14 +0100
Page 2 of 2 — ← Prev page 1 [2]
| From | André Malo <ndparker@gmail.com> |
|---|---|
| Date | 2012-08-06 20:19 +0200 |
| Message-ID | <11795205.embGBpUICj@news.perlig.de> |
| In reply to | #26625 |
* Tom P wrote:
> consider a nested loop algorithm -
>
> for i in range(100):
> for j in range(100):
> do_something(i,j)
>
> Now, suppose I don't want to use i = 0 and j = 0 as initial values, but
> some other values i = N and j = M, and I want to iterate through all
> 10,000 values in sequence - is there a neat python-like way to this? I
> realize I can do things like use a variable for k in range(10000): and
> then derive values for i and j from k, but I'm wondering if there's
> something less clunky.
you mean:
do_something((i + N) % 100, (j + M) % 100)
?
I'd define my own range function doing exactly that.
def rrange(count, start=0):
for j in xrange(count):
yield (j + start) % count
(untested)
Or use some itertools magic for that. It might be faster.
nd
--
"Umfassendes Werk (auch fuer Umsteiger vom Apache 1.3)"
-- aus einer Rezension
<http://pub.perlig.de/books.html#apache2>
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| From | Dennis Lee Bieber <wlfraed@ix.netcom.com> |
|---|---|
| Date | 2012-08-06 15:31 -0400 |
| Message-ID | <mailman.3025.1344281720.4697.python-list@python.org> |
| In reply to | #26625 |
On Mon, 06 Aug 2012 17:52:31 +0200, Tom P <werotizy@freent.dd> declaimed
the following in gmane.comp.python.general:
> consider a nested loop algorithm -
>
> for i in range(100):
> for j in range(100):
> do_something(i,j)
>
> Now, suppose I don't want to use i = 0 and j = 0 as initial values, but
> some other values i = N and j = M, and I want to iterate through all
range() takes an optional "start" and "increment"
for i in range(istart, istart+ilength):
for j in range(jstart, jstart+jlength):
do_something(i, j)
where "istart" is N and "jstart" is M
> 10,000 values in sequence - is there a neat python-like way to this? I
and ilength|jlength is 100
--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com HTTP://wlfraed.home.netcom.com/
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| From | Arnaud Delobelle <arnodel@gmail.com> |
|---|---|
| Date | 2012-08-06 21:14 +0100 |
| Message-ID | <mailman.3028.1344284069.4697.python-list@python.org> |
| In reply to | #26625 |
On 6 August 2012 16:52, Tom P <werotizy@freent.dd> wrote:
> consider a nested loop algorithm -
>
> for i in range(100):
> for j in range(100):
> do_something(i,j)
>
> Now, suppose I don't want to use i = 0 and j = 0 as initial values, but some
> other values i = N and j = M, and I want to iterate through all 10,000
> values in sequence - is there a neat python-like way to this? I realize I
> can do things like use a variable for k in range(10000): and then derive
> values for i and j from k, but I'm wondering if there's something less
> clunky.
For example:
for i in range(100):
for j in range(100):
do_something((i + N)%100, (j + N)%100)
Cheers,
--
Arnaud
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