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Re: testing if a list contains a sublist

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Am 16.08.2011 10:00, schrieb Laszlo Nagy:
> 
>> Error free? Consider this stated requirement:
>>> l1 = [1,2,2,], l2 = [1,2,3,4,5] ->  l1 is not contained in l2
> If you look it the strict way, "containment" relation for lists is meant
> this way:
> 
> 
> l1 = []
> l2 = [1,l1,2]   # l2 CONTAINS l1
> 
> But you are right, I was wrong. So let's clarify what the OP wants!
> 
> For example:
> 
> l1 = [1,2,2,], l2 = [2,1,2,3,4,5]
I dont care about this case, because all list are ordered for me.

I've chosen the following solution

> def _list_contained_in_list(l1,l2):
>     d1 = {}
>     d2 = {}
>     for i in l1:
>         if i in d1:
>             d1[i] += 1
>         else:
>             d1[i] = 1
>     for i in l2:
>         if i in d2:
>             d2[i] += 1
>         else:
>             d2[i] = 1
>     if not all([k in d2.keys() for k in d1.keys()]):
>         return false    
>     return all([d1[i] <= d2[i] for i in d1])


greatz Johannes

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testing if a list contains a sublist Johannes <dajo.mail@web.de> - 2011-08-16 01:26 +0200
  Re: testing if a list contains a sublist Roy Smith <roy@panix.com> - 2011-08-15 20:53 -0400
    Re: testing if a list contains a sublist Laszlo Nagy <gandalf@shopzeus.com> - 2011-08-16 08:51 +0200
      Re: testing if a list contains a sublist alex23 <wuwei23@gmail.com> - 2011-08-16 00:19 -0700
      Re: testing if a list contains a sublist alex23 <wuwei23@gmail.com> - 2011-08-16 00:14 -0700
        Re: testing if a list contains a sublist Laszlo Nagy <gandalf@shopzeus.com> - 2011-08-16 10:00 +0200
        Re: testing if a list contains a sublist Johannes <dajo.mail@web.de> - 2011-08-16 17:26 +0200
      Re: testing if a list contains a sublist ChasBrown <cbrown@cbrownsystems.com> - 2011-08-16 00:24 -0700
    Re: testing if a list contains a sublist Alain Ketterlin <alain@dpt-info.u-strasbg.fr> - 2011-08-16 14:23 +0200
      Re: testing if a list contains a sublist Roy Smith <roy@panix.com> - 2011-08-16 08:53 -0400
      Re: testing if a list contains a sublist nn <pruebauno@latinmail.com> - 2011-08-16 07:53 -0700
        Re: testing if a list contains a sublist Laszlo Nagy <gandalf@shopzeus.com> - 2011-08-16 17:17 +0200
          Re: testing if a list contains a sublist Alain Ketterlin <alain@dpt-info.u-strasbg.fr> - 2011-08-16 17:39 +0200
        Re: testing if a list contains a sublist Neil Cerutti <neilc@norwich.edu> - 2011-08-16 17:45 +0000
  Re: testing if a list contains a sublist Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-08-16 12:12 +1000
    Re: testing if a list contains a sublist Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-08-16 18:19 +1000
  Re: testing if a list contains a sublist ChasBrown <cbrown@cbrownsystems.com> - 2011-08-15 23:14 -0700
  Re: testing if a list contains a sublist ChasBrown <cbrown@cbrownsystems.com> - 2011-08-15 23:13 -0700
  Re: testing if a list contains a sublist ChasBrown <cbrown@cbrownsystems.com> - 2011-08-15 23:14 -0700
    Re: testing if a list contains a sublist Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-08-16 18:37 +1000
      Re: testing if a list contains a sublist ChasBrown <cbrown@cbrownsystems.com> - 2011-08-16 21:13 -0700
  Re: testing if a list contains a sublist Nobody <nobody@nowhere.com> - 2011-08-16 12:21 +0100
    Re: testing if a list contains a sublist John Posner <jjposner@codicesoftware.com> - 2011-08-16 09:57 -0400
    Re: testing if a list contains a sublist John Posner <jjposner@optimum.net> - 2011-08-16 09:57 -0400
      Re: testing if a list contains a sublist Nobody <nobody@nowhere.com> - 2011-08-17 13:28 +0100
  Re: testing if a list contains a sublist Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-08-20 12:10 +1000

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