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Re: Why this code works in python3, but not python 2:

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From Joshua Landau <joshua.landau.ws@gmail.com>
Date Thu, 4 Jul 2013 06:10:21 +0100
Subject Re: Why this code works in python3, but not python 2:
To alex23 <wuwei23@gmail.com>
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On 4 July 2013 05:47, alex23 <wuwei23@gmail.com> wrote:
> On 4/07/2013 2:12 PM, Joshua Landau wrote:
>>
>> On 4 July 2013 04:52, Maciej Dziardziel <fiedzia@gmail.com> wrote:
>>>
>>> def foo(*args, bar=1, **kwargs):
>>>      pass
>
>
>> Try "foo(1)" and it will fail -- "bar" needs to be given as a keyword.
>
>
> No it won't, because it is supplied with a default.

Pah! I'm not even thinking.

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Thread

Why this code works in python3, but not python 2: Maciej Dziardziel <fiedzia@gmail.com> - 2013-07-03 20:52 -0700
  Re: Why this code works in python3, but not python 2: alex23 <wuwei23@gmail.com> - 2013-07-04 14:05 +1000
    Re: Why this code works in python3, but not python 2: Maciej Dziardziel <fiedzia@gmail.com> - 2013-07-03 21:31 -0700
  Re: Why this code works in python3, but not python 2: Chris Angelico <rosuav@gmail.com> - 2013-07-04 14:10 +1000
  Re: Why this code works in python3, but not python 2: Joshua Landau <joshua.landau.ws@gmail.com> - 2013-07-04 05:12 +0100
    Re: Why this code works in python3, but not python 2: alex23 <wuwei23@gmail.com> - 2013-07-04 14:47 +1000
      Re: Why this code works in python3, but not python 2: Joshua Landau <joshua.landau.ws@gmail.com> - 2013-07-04 06:10 +0100

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