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Re: Why this code works in python3, but not python 2:

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On 4/07/2013 2:12 PM, Joshua Landau wrote:
> On 4 July 2013 04:52, Maciej Dziardziel <fiedzia@gmail.com> wrote:
>> def foo(*args, bar=1, **kwargs):
>>      pass

> Try "foo(1)" and it will fail -- "bar" needs to be given as a keyword.

No it won't, because it is supplied with a default. You may be
confusing it with the requirement that `bar` must be given as a keyword
in order for it to override the default, compared to the way this would
need to be written in Py2:

     def foo(bar=1, *args, **kwargs):
         ...

...in which case `bar` could be assigned to by the first positional
argument.

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Why this code works in python3, but not python 2: Maciej Dziardziel <fiedzia@gmail.com> - 2013-07-03 20:52 -0700
  Re: Why this code works in python3, but not python 2: alex23 <wuwei23@gmail.com> - 2013-07-04 14:05 +1000
    Re: Why this code works in python3, but not python 2: Maciej Dziardziel <fiedzia@gmail.com> - 2013-07-03 21:31 -0700
  Re: Why this code works in python3, but not python 2: Chris Angelico <rosuav@gmail.com> - 2013-07-04 14:10 +1000
  Re: Why this code works in python3, but not python 2: Joshua Landau <joshua.landau.ws@gmail.com> - 2013-07-04 05:12 +0100
    Re: Why this code works in python3, but not python 2: alex23 <wuwei23@gmail.com> - 2013-07-04 14:47 +1000
      Re: Why this code works in python3, but not python 2: Joshua Landau <joshua.landau.ws@gmail.com> - 2013-07-04 06:10 +0100

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