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| From | Joshua Landau <joshua.landau.ws@gmail.com> |
| Date | Thu, 4 Jul 2013 05:12:26 +0100 |
| Subject | Re: Why this code works in python3, but not python 2: |
| To | Maciej Dziardziel <fiedzia@gmail.com> |
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On 4 July 2013 04:52, Maciej Dziardziel <fiedzia@gmail.com> wrote: > Out of curiosity: Does anyone know why the code below is valid in python3, but not python2: > > def foo(*args, bar=1, **kwargs): > pass Python 3 gained syntax for keyword-only arguments. Try "foo(1)" and it will fail -- "bar" needs to be given as a keyword. This is because it comes after a *-expression. You can also do "def foo(*, bar=1)" if you want bar to be keyword-only without accepting any number of positional arguments. Python 2 does not have these, and doesn't understand the syntax for them.
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Why this code works in python3, but not python 2: Maciej Dziardziel <fiedzia@gmail.com> - 2013-07-03 20:52 -0700
Re: Why this code works in python3, but not python 2: alex23 <wuwei23@gmail.com> - 2013-07-04 14:05 +1000
Re: Why this code works in python3, but not python 2: Maciej Dziardziel <fiedzia@gmail.com> - 2013-07-03 21:31 -0700
Re: Why this code works in python3, but not python 2: Chris Angelico <rosuav@gmail.com> - 2013-07-04 14:10 +1000
Re: Why this code works in python3, but not python 2: Joshua Landau <joshua.landau.ws@gmail.com> - 2013-07-04 05:12 +0100
Re: Why this code works in python3, but not python 2: alex23 <wuwei23@gmail.com> - 2013-07-04 14:47 +1000
Re: Why this code works in python3, but not python 2: Joshua Landau <joshua.landau.ws@gmail.com> - 2013-07-04 06:10 +0100
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