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Groups > comp.lang.python > #36528
| Newsgroups | comp.lang.python |
|---|---|
| Date | 2013-01-09 15:24 -0800 |
| References | <25c1f151-7323-42de-833f-15639b6eff71@googlegroups.com> <mailman.300.1357697174.2939.python-list@python.org> |
| Subject | Re: Best way to do this? List loop (matrix?) iteration |
| From | andydtaylor@gmail.com |
| Message-ID | <mailman.345.1357773894.2939.python-list@python.org> (permalink) |
Thanks for your help - this is what I did - though it's probably obvious to most people reading this.
for rowcount in range (0, stn_count):
row_durations.append(stn_list_short[rowcount])
for colcount in range (0, stn_count):
# 3. Determine Station pairs for API query
query_origin_stop = stn_list_long[rowcount]
query_destination_stop = stn_list_long[colcount]
# 4. Paths for determining duration. "station x = station x" has journey time 0
# 4a. Stations are SAME
....etc. and this part works! I am now stuck on something else though, but I'll start a new topic for that.
Thanks
Andy
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Best way to do this? List loop (matrix?) iteration andydtaylor@gmail.com - 2013-01-08 16:19 -0800
Re: Best way to do this? List loop (matrix?) iteration Mitya Sirenef <msirenef@lightbird.net> - 2013-01-08 19:33 -0500
Re: Best way to do this? List loop (matrix?) iteration Chris Angelico <rosuav@gmail.com> - 2013-01-09 13:06 +1100
Re: Best way to do this? List loop (matrix?) iteration andydtaylor@gmail.com - 2013-01-09 15:24 -0800
Re: Best way to do this? List loop (matrix?) iteration Dave Angel <d@davea.name> - 2013-01-09 18:49 -0500
Re: Best way to do this? List loop (matrix?) iteration andydtaylor@gmail.com - 2013-01-09 15:24 -0800
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