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Re: Best way to do this? List loop (matrix?) iteration

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On Wed, Jan 9, 2013 at 11:19 AM,  <andydtaylor@gmail.com> wrote:
>    stn_count = len(stn_list_short)
>    for rowcount in range (0, stn_count):
>       for colcount in range (0, stn_count):
>          print stn_list_long[rowcount] stn_list_long[colcount]

First off, you can iterate over the list directly:

for row in stn_list_short:
  for col in stn_list_short:
    print row + col

(I'm not sure what your code was doing with the print line, because it
ought to have failed. Explicit concatenation will work.)

Secondly, you can make a list of all of those pairs with a compact
notation called a comprehension:

pairs = [row + col for row in stn_list_short for col in stn_list_short]

That covers your requirement #2, giving you a full list of all of
them. How big is k going to be? Storing the whole list in memory will
get a little awkward if you have very large k; on this system, I
started seeing performance issues with a thousand elements in the
list, but you could probably go to ten thousand (ie a hundred million
pairs) if you have a decent bit of RAM.

ChrisA

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Best way to do this? List loop (matrix?) iteration andydtaylor@gmail.com - 2013-01-08 16:19 -0800
  Re: Best way to do this? List loop (matrix?) iteration Mitya Sirenef <msirenef@lightbird.net> - 2013-01-08 19:33 -0500
  Re: Best way to do this? List loop (matrix?) iteration Chris Angelico <rosuav@gmail.com> - 2013-01-09 13:06 +1100
    Re: Best way to do this? List loop (matrix?) iteration andydtaylor@gmail.com - 2013-01-09 15:24 -0800
      Re: Best way to do this? List loop (matrix?) iteration Dave Angel <d@davea.name> - 2013-01-09 18:49 -0500
    Re: Best way to do this? List loop (matrix?) iteration andydtaylor@gmail.com - 2013-01-09 15:24 -0800

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