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| Date | Fri, 13 Mar 2015 14:38:51 -0400 |
| Subject | Re: regex help |
| From | Larry Martell <larry.martell@gmail.com> |
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On Fri, Mar 13, 2015 at 1:29 PM, MRAB <python@mrabarnett.plus.com> wrote: > On 2015-03-13 16:05, Larry Martell wrote: >> >> I need to remove all trailing zeros to the right of the decimal point, >> but leave one zero if it's whole number. For example, if I have this: >> >> >> 14S,5.0000000000000000,4.56862745000000,3.7272727272727271,3.3947368421052630,5.7307692307692308,5.7547169811320753,4.9423076923076925,5.7884615384615383,5.137254901960000 >> >> I want to end up with: >> >> >> 14S,5.0,4.56862745,3.7272727272727271,3.394736842105263,5.7307692307692308,5.7547169811320753,4.9423076923076925,5.7884615384615383,5.13725490196 >> >> I have a regex to remove the zeros: >> >> '0+[,$]', '' >> >> But I can't figure out how to get the 5.0000000000000000 to be 5.0. >> I've been messing with the negative lookbehind, but I haven't found >> one that works for this. >> > Search: (\.\d+?)0+\b > Replace: \1 > > which is: > > re.sub(r'(\.\d+?)0+\b', r'\1', string) Thanks! That works perfectly.
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Re: regex help Larry Martell <larry.martell@gmail.com> - 2015-03-13 14:38 -0400
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