Re: regex help

References	<CACwCsY6cN6+mZVYWnMpKGsXg6jd7Y8Gav9DC7HkXcPtU-pDXDw@mail.gmail.com> <55031E80.6030904@mrabarnett.plus.com>
Date	2015-03-13 14:38 -0400
Subject	Re: regex help
From	Larry Martell <larry.martell@gmail.com>
Newsgroups	comp.lang.python
Message-ID	<mailman.335.1426271938.21433.python-list@python.org> (permalink)

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On Fri, Mar 13, 2015 at 1:29 PM, MRAB <python@mrabarnett.plus.com> wrote:
> On 2015-03-13 16:05, Larry Martell wrote:
>>
>> I need to remove all trailing zeros to the right of the decimal point,
>> but leave one zero if it's whole number. For example, if I have this:
>>
>>
>> 14S,5.0000000000000000,4.56862745000000,3.7272727272727271,3.3947368421052630,5.7307692307692308,5.7547169811320753,4.9423076923076925,5.7884615384615383,5.137254901960000
>>
>> I want to end up with:
>>
>>
>> 14S,5.0,4.56862745,3.7272727272727271,3.394736842105263,5.7307692307692308,5.7547169811320753,4.9423076923076925,5.7884615384615383,5.13725490196
>>
>> I have a regex to remove the zeros:
>>
>> '0+[,$]', ''
>>
>> But I can't figure out how to get the 5.0000000000000000 to be 5.0.
>> I've been messing with the negative lookbehind, but I haven't found
>> one that works for this.
>>
> Search: (\.\d+?)0+\b
> Replace: \1
>
> which is:
>
> re.sub(r'(\.\d+?)0+\b', r'\1', string)

Thanks! That works perfectly.

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Re: regex help Larry Martell <larry.martell@gmail.com> - 2015-03-13 14:38 -0400

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