Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > comp.lang.python > #47929

Re: Split a list into two parts based on a filter?

Path csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!xlned.com!feeder1.xlned.com!newsfeed.xs4all.nl!newsfeed1.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail
Return-Path <oscar.j.benjamin@gmail.com>
X-Original-To python-list@python.org
Delivered-To python-list@mail.python.org
X-Spam-Status OK 0.012
X-Spam-Evidence '*H*': 0.98; '*S*': 0.00; 'else:': 0.03; 'subject:two': 0.07; 'subject:into': 0.09; 'cc:addr:python-list': 0.11; 'thread': 0.14; 'posted': 0.15; 'cc:name:python list': 0.16; 'reedy': 0.16; 'rewriting': 0.16; 'subject:based': 0.16; 'wrote:': 0.18; 'cc:addr:python.org': 0.22; 'cc:2**0': 0.24; 'header:In- Reply-To:1': 0.27; 'statement': 0.30; 'subject:list': 0.30; 'message-id:@mail.gmail.com': 0.30; 'code': 0.31; 'this.': 0.32; "we're": 0.32; 'but': 0.35; 'received:google.com': 0.35; 'subject:?': 0.36; 'skip:o 20': 0.38; 'back': 0.62; 'skip:n 10': 0.64; 'started.': 0.68; 'oscar': 0.84; '2013': 0.98
DKIM-Signature v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:from:date:message-id:subject:to :cc:content-type; bh=ykzSaKEzVsasHe9NnUF0jZ2UKAPrrZBp2uoAU6Ku53g=; b=lwisW0vWxLZvh3JTOG+oykKMYQnJPD6/XQ9eb2qUkEEmDf+FBIlS9/Uwks/N03eTsO LzzWaDU4sjmiF56VA0Phgjla0+LzFt+OffVwkC6Xx1EvlZZriuglKBVY5bVHC1DmYxkC eAErj5Mr/pVF3pefrZ5CU5wHPCZ0rBYPuQYjpqAiqKtdCPhkd3id2lWGH9xoJiXauZt+ gCI/XRvN+WtlILiLgljknRD5J8EAdLYg79TU2cCtSXB/xCRro5V1FDYeQCvOmKW/iOxt 5XZ6UCB+CBBgZNLikfmaY9I7cpNvuj7rrqORpFQPeeKnvuNxGQBOLAX2y1bwo4w5dNF/ pxEQ==
X-Received by 10.52.27.20 with SMTP id p20mr9524342vdg.123.1371116613803; Thu, 13 Jun 2013 02:43:33 -0700 (PDT)
MIME-Version 1.0
In-Reply-To <kpafnn$vp2$1@ger.gmane.org>
References <kp5d9e$2hf$1@panix2.panix.com> <mailman.2992.1370904643.3114.python-list@python.org> <roy-12F8FA.00111311062013@news.panix.com> <mailman.3023.1370964449.3114.python-list@python.org> <roy-10ED1B.20334411062013@news.panix.com> <CANCy3MzHXNp-m-fKiOr0A+=gvwUgoQS2KaWuWjGgStfk+JQsbQ@mail.gmail.com> <kpa7jo$3um$1@ger.gmane.org> <CAA=1kxR4c+j_iL4-KeFtXB675gX8F982Owu0a-MHGoKQG6wprg@mail.gmail.com> <kpafnn$vp2$1@ger.gmane.org>
From Oscar Benjamin <oscar.j.benjamin@gmail.com>
Date Thu, 13 Jun 2013 10:43:13 +0100
Subject Re: Split a list into two parts based on a filter?
To Terry Reedy <tjreedy@udel.edu>
Content-Type text/plain; charset=ISO-8859-1
Cc Python List <python-list@python.org>
X-BeenThere python-list@python.org
X-Mailman-Version 2.1.15
Precedence list
List-Id General discussion list for the Python programming language <python-list.python.org>
List-Unsubscribe <http://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe>
List-Archive <http://mail.python.org/pipermail/python-list/>
List-Post <mailto:python-list@python.org>
List-Help <mailto:python-list-request@python.org?subject=help>
List-Subscribe <http://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe>
Newsgroups comp.lang.python
Message-ID <mailman.3178.1371116623.3114.python-list@python.org> (permalink)
Lines 21
NNTP-Posting-Host 2001:888:2000:d::a6
X-Trace 1371116623 news.xs4all.nl 15882 [2001:888:2000:d::a6]:43813
X-Complaints-To abuse@xs4all.nl
Xref csiph.com comp.lang.python:47929

Show key headers only | View raw

On 12 June 2013 19:47, Terry Reedy <tjreedy@udel.edu> wrote:
> The proper loop statement
>
> for s in songs:
>     (new_songs if s.is_new() else old_songs).append(s)

I think I would just end up rewriting this as

for s in songs:
    if s.is_new():
        new_songs.append(s)
    else:
        old_songs.append(s)

but then we're back where we started. I don't think any of the
solutions posted in this thread have been better than this. If you
want to make this a nice one-liner then just put this code in a
function.


Oscar

Back to comp.lang.python | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread

Thread

Split a list into two parts based on a filter? roy@panix.com (Roy Smith) - 2013-06-10 16:34 -0400
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 08:50 +1000
  Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 00:50 +0200
    Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 00:11 -0400
      Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:27 +0300
        Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:33 -0400
          Re: Split a list into two parts based on a filter? Phil Connell <pconnell@gmail.com> - 2013-06-12 07:32 +0100
            Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-12 07:39 -0400
              Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 12:51 +0100
              Re: Split a list into two parts based on a filter? Jussi Piitulainen <jpiitula@ling.helsinki.fi> - 2013-06-12 15:06 +0300
              Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:07 -0400
          Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-12 19:28 +0300
          Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 17:57 +0100
          Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:47 -0400
          Re: Split a list into two parts based on a filter? Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-06-13 10:43 +0100
  Re: Split a list into two parts based on a filter? Chris Rebert <clp2@rebertia.com> - 2013-06-10 16:03 -0700
  Re: Split a list into two parts based on a filter? Tim Chase <python.list@tim.thechases.com> - 2013-06-10 18:10 -0500
  Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 00:08 +0100
    Re: Split a list into two parts based on a filter? alex23 <wuwei23@gmail.com> - 2013-06-11 17:44 -0700
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 09:12 +1000
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 02:11 +0200
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 08:43 +0200
  Re: Split a list into two parts based on a filter? Jonas Geiregat <jonas@geiregat.org> - 2013-06-11 08:47 +0200
  Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 14:48 +0100
    Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 09:37 -0700
      Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 18:05 +0100
        Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 10:23 -0700
          Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:37 +1000
            Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 11:13 -0700
          Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 19:05 +0100
  Re: Split a list into two parts based on a filter? Joshua Landau <joshua.landau.ws@gmail.com> - 2013-06-11 15:22 +0100
  Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:28 +0300
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:28 +1000
    Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:12 -0400
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:13 +0200
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:18 +0200
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 04:27 +1000
  Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 22:22 +0200

csiph-web