Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]


Groups > comp.lang.python > #47743

Re: Split a list into two parts based on a filter?

Path csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!goblin1!goblin.stu.neva.ru!news2.euro.net!newsfeed.xs4all.nl!newsfeed4.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail
Return-Path <pconnell@gmail.com>
X-Original-To python-list@python.org
Delivered-To python-list@mail.python.org
X-Spam-Status OK 0.002
X-Spam-Evidence '*H*': 1.00; '*S*': 0.00; 'syntax': 0.04; 'true,': 0.05; 'memory.': 0.07; 'subject:two': 0.07; '[],': 0.09; 'iterate': 0.09; 'subject:into': 0.09; 'cc:addr:python-list': 0.11; '&gt;&gt;': 0.16; '[none]': 0.16; 'discarded.': 0.16; 'expression.': 0.16; 'iterator': 0.16; 'lambda': 0.16; 'path:': 0.16; 'roy': 0.16; 'smith"': 0.16; 'subject:based': 0.16; '\xc2\xa0i': 0.16; ':-)': 0.16; 'wrote:': 0.18; 'trying': 0.19; 'thanks.': 0.20; 'code,': 0.22; 'memory': 0.22; 'email addr:gmail.com&gt;': 0.22; 'cc:addr:python.org': 0.22; 'rid': 0.24; 'cheers,': 0.24; 'cc:2**0': 0.24; 'cc:no real name:2**0': 0.24; '&gt;': 0.26; 'pass': 0.26; 'least': 0.26; 'gets': 0.27; 'header:In-Reply-To:1': 0.27; 'idea': 0.28; 'point': 0.28; 'skip:& 60': 0.30; 'subject:list': 0.30; 'message-id:@mail.gmail.com': 0.30; "i'm": 0.30; 'url:mailman': 0.30; '(although': 0.31; 'constant': 0.31; 'figure': 0.32; 'url:python': 0.33; 'continuing': 0.33; 'could': 0.34; 'created': 0.35; 'requirement': 0.35; 'but': 0.35; 'received:google.com': 0.35; 'url:listinfo': 0.36; 'useful': 0.36; 'thanks': 0.36; 'subject:?': 0.36; 'url:org': 0.36; 'list': 0.37; 'skip:o 20': 0.38; '8bit%:86': 0.38; 'anything': 0.39; 'sure': 0.39; 'url:mail': 0.40; 'course': 0.61; 'kind': 0.63; 'more': 0.64; 'smith': 0.68; 'article': 0.77; 'phil': 0.84; 'received:mail-ob0-x22f.google.com': 0.84; 'usage.': 0.84; 'technique': 0.93; '2013': 0.98
DKIM-Signature v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:date:message-id:subject:from:to :cc:content-type; bh=FwfI4B7vHQiXXYi1e5SCYGLdOzPSMpxyrJvK4eDj1iQ=; b=EAQ4e9Q+/Qq9O/tJxbt71ZtqBQIyTHzdJcMPcR8815bDSQxdAf0U8XyF3eJ0yUzU3l UqVQLlA5s2S7rwc00+c2ohsXm5ZGOXHugpaDv9o9GmiVBtIp5JZ+wAoh+LW4fL4/dvcv 2sXcmAzbh+4E9HKBGpAwrdJoTwrl8rwv8AIZ225JxW1KXvhQ/Vb6cVSMhcQWNq6r7ONU VDAWBImLmUs7rTrFbnYtyWaotTDzDw30DqxjU4dn5iN0eaDSByJK4mPH8YdpdRsI1ZVD ZEmtMNyw2jbHYXdt+zQvf7eGTU6uDBVXjM9ogSzmjeUoJ0/87TIZ9lTb02zFiqXGhag7 qihQ==
MIME-Version 1.0
X-Received by 10.60.143.41 with SMTP id sb9mr7142394oeb.102.1371018746403; Tue, 11 Jun 2013 23:32:26 -0700 (PDT)
In-Reply-To <roy-10ED1B.20334411062013@news.panix.com>
References <kp5d9e$2hf$1@panix2.panix.com> <mailman.2992.1370904643.3114.python-list@python.org> <roy-12F8FA.00111311062013@news.panix.com> <mailman.3023.1370964449.3114.python-list@python.org> <roy-10ED1B.20334411062013@news.panix.com>
Date Wed, 12 Jun 2013 07:32:26 +0100
Subject Re: Split a list into two parts based on a filter?
From Phil Connell <pconnell@gmail.com>
To Roy Smith <roy@panix.com>
Content-Type multipart/alternative; boundary=047d7b3a89fc5c6d4104deef2d53
Cc python-list@python.org
X-BeenThere python-list@python.org
X-Mailman-Version 2.1.15
Precedence list
List-Id General discussion list for the Python programming language <python-list.python.org>
List-Unsubscribe <http://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe>
List-Archive <http://mail.python.org/pipermail/python-list/>
List-Post <mailto:python-list@python.org>
List-Help <mailto:python-list-request@python.org?subject=help>
List-Subscribe <http://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe>
Newsgroups comp.lang.python
Message-ID <mailman.3050.1371018754.3114.python-list@python.org> (permalink)
Lines 113
NNTP-Posting-Host 2001:888:2000:d::a6
X-Trace 1371018755 news.xs4all.nl 15930 [2001:888:2000:d::a6]:51365
X-Complaints-To abuse@xs4all.nl
Xref csiph.com comp.lang.python:47743

Show key headers only | View raw


[Multipart message — attachments visible in raw view] - view raw

On 12 Jun 2013 01:36, "Roy Smith" <roy@panix.com> wrote:
>
> In article <mailman.3023.1370964449.3114.python-list@python.org>,
>  Serhiy Storchaka <storchaka@gmail.com> wrote:
>
> > 11.06.13 07:11, Roy Smith написав(ла):
> > > In article <mailman.2992.1370904643.3114.python-list@python.org>,
> > >   Roel Schroeven <roel@roelschroeven.net> wrote:
> > >
> > >> new_songs, old_songs = [], []
> > >> [(new_songs if s.is_new() else old_songs).append(s) for s in songs]
> > >
> > > Thanks kind of neat, thanks.
> > >
> > > I'm trying to figure out what list gets created and discarded.  I
think
> > > it's [None] * len(songs).
> >
> > It is the same as your klunky code, but consumes more memory.
>
> Well, continuing down this somewhat bizarre path:
>
> new_songs, old_songs = [], []
> itertools.takewhile(
>     lambda x: True,
>     (new_songs if s.is_new() else old_songs).append(s) for s in songs)
>     )
>
> I'm not sure I got the syntax exactly right, but the idea is anything
> that will iterate over a generator expression.  That at least gets rid
> of the memory requirement to hold the throw-away list :-)

You could equivalently pass the generator to deque() with maxlen=0 - this
consumes the iterator with constant memory usage.

We are of course firmly in the twilight zone at this point (although this
can be a useful technique in general).

Cheers,
Phil

>
> --
> http://mail.python.org/mailman/listinfo/python-list
>

Back to comp.lang.python | Previous | NextPrevious in thread | Next in thread | Find similar | Unroll thread


Thread

Split a list into two parts based on a filter? roy@panix.com (Roy Smith) - 2013-06-10 16:34 -0400
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 08:50 +1000
  Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 00:50 +0200
    Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 00:11 -0400
      Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:27 +0300
        Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:33 -0400
          Re: Split a list into two parts based on a filter? Phil Connell <pconnell@gmail.com> - 2013-06-12 07:32 +0100
            Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-12 07:39 -0400
              Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 12:51 +0100
              Re: Split a list into two parts based on a filter? Jussi Piitulainen <jpiitula@ling.helsinki.fi> - 2013-06-12 15:06 +0300
              Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:07 -0400
          Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-12 19:28 +0300
          Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 17:57 +0100
          Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:47 -0400
          Re: Split a list into two parts based on a filter? Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-06-13 10:43 +0100
  Re: Split a list into two parts based on a filter? Chris Rebert <clp2@rebertia.com> - 2013-06-10 16:03 -0700
  Re: Split a list into two parts based on a filter? Tim Chase <python.list@tim.thechases.com> - 2013-06-10 18:10 -0500
  Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 00:08 +0100
    Re: Split a list into two parts based on a filter? alex23 <wuwei23@gmail.com> - 2013-06-11 17:44 -0700
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 09:12 +1000
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 02:11 +0200
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 08:43 +0200
  Re: Split a list into two parts based on a filter? Jonas Geiregat <jonas@geiregat.org> - 2013-06-11 08:47 +0200
  Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 14:48 +0100
    Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 09:37 -0700
      Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 18:05 +0100
        Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 10:23 -0700
          Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:37 +1000
            Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 11:13 -0700
          Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 19:05 +0100
  Re: Split a list into two parts based on a filter? Joshua Landau <joshua.landau.ws@gmail.com> - 2013-06-11 15:22 +0100
  Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:28 +0300
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:28 +1000
    Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:12 -0400
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:13 +0200
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:18 +0200
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 04:27 +1000
  Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 22:22 +0200

csiph-web