Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]


Groups > comp.lang.python > #47617

Re: Split a list into two parts based on a filter?

Path csiph.com!usenet.pasdenom.info!gegeweb.org!de-l.enfer-du-nord.net!feeder2.enfer-du-nord.net!feeds.phibee-telecom.net!newsfeed.xs4all.nl!newsfeed1.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail
Return-Path <rosuav@gmail.com>
X-Original-To python-list@python.org
Delivered-To python-list@mail.python.org
X-Spam-Status OK 0.025
X-Spam-Evidence '*H*': 0.95; '*S*': 0.00; 'anyway.': 0.05; 'subject:two': 0.07; 'subject:into': 0.09; 'def': 0.12; 'deque': 0.16; 'from:addr:rosuav': 0.16; 'from:name:chris angelico': 0.16; 'iterable': 0.16; 'iterator': 0.16; 'subject:based': 0.16; 'sure.': 0.16; 'modification': 0.16; 'wrote:': 0.18; '>>>': 0.22; 'long,': 0.26; 'gets': 0.27; 'header:In-Reply-To:1': 0.27; 'chris': 0.29; 'am,': 0.29; 'tim': 0.29; 'subject:list': 0.30; 'message-id:@mail.gmail.com': 0.30; "i'm": 0.30; 'chase': 0.31; 'lists': 0.32; 'maybe': 0.34; "i'd": 0.34; 'received:209.85': 0.35; 'received:209.85.220': 0.35; 'but': 0.35; 'received:google.com': 0.35; 'version': 0.36; 'really': 0.36; 'false': 0.36; 'subject:?': 0.36; 'two': 0.37; 'received:209': 0.37; 'performance': 0.37; 'to:addr:python-list': 0.38; 'to:addr:python.org': 0.39; 'either': 0.39; 'major': 0.40; 'here:': 0.62; 'making': 0.63; 'optimized': 0.68; 'hand': 0.80; 'end.': 0.84; 'heh.': 0.84; '2013': 0.98
DKIM-Signature v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:date:message-id:subject:from:to :content-type; bh=OVXzfoVB4yeusLC7L+M9hVSSO81CBow4AzpYE1thclk=; b=tG9Bjm34BBQ2GJmQOOtxCJumasEmWMzetmIFakiOxfIpT+nWFJjxdVVv5ZYeEYPPj1 D8grekpxqWwMH1d52+2I9ETAbVusUZyqJ7m5dni2z33GiqjtuRPWjnEtrK9GRLlnvOWZ lWzXgpz0SbmkmpL4g3llR1H/pbbHj/PdqT4YN14gs/E89V2WhRV47oRwC44sKOzBtVzj f216KewN4krWxhmeP0mMH/IxHjHIZ/wZUQvDf/enU85yYmL/Pe3/B5ZNPVDB5S2N2/kO JsdcpARCkNRHOKLW2q/BiUTcQ5xiPb0knkpXr7QAFR908pYnDzmPwGCbnRLjKu61zn7v 0tVg==
MIME-Version 1.0
X-Received by 10.52.164.163 with SMTP id yr3mr5901637vdb.76.1370905978653; Mon, 10 Jun 2013 16:12:58 -0700 (PDT)
In-Reply-To <20130610181022.42c05db6@bigbox.christie.dr>
References <kp5d9e$2hf$1@panix2.panix.com> <CAPTjJmrDNe8ASxD8xsok=-_zoDRrUZjHydYSm3G_SJy8T2a_5A@mail.gmail.com> <20130610181022.42c05db6@bigbox.christie.dr>
Date Tue, 11 Jun 2013 09:12:58 +1000
Subject Re: Split a list into two parts based on a filter?
From Chris Angelico <rosuav@gmail.com>
To python-list@python.org
Content-Type text/plain; charset=ISO-8859-1
X-BeenThere python-list@python.org
X-Mailman-Version 2.1.15
Precedence list
List-Id General discussion list for the Python programming language <python-list.python.org>
List-Unsubscribe <http://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe>
List-Archive <http://mail.python.org/pipermail/python-list/>
List-Post <mailto:python-list@python.org>
List-Help <mailto:python-list-request@python.org?subject=help>
List-Subscribe <http://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe>
Newsgroups comp.lang.python
Message-ID <mailman.2997.1370905986.3114.python-list@python.org> (permalink)
Lines 24
NNTP-Posting-Host 2001:888:2000:d::a6
X-Trace 1370905986 news.xs4all.nl 15902 [2001:888:2000:d::a6]:38546
X-Complaints-To abuse@xs4all.nl
Xref csiph.com comp.lang.python:47617

Show key headers only | View raw


On Tue, Jun 11, 2013 at 9:10 AM, Tim Chase
<python.list@tim.thechases.com> wrote:
> On 2013-06-11 08:50, Chris Angelico wrote:
>> The iterator version strikes my fancy. Maybe this isn't of use to
>> you, but I'm going to try my hand at making one anyway.
>>
>> >>> def iterpartition(pred,it):
>>       """Partition an iterable based on a predicate.
>>
>>       Returns two iterables, for those with pred False and those
>> True.""" falses,trues=[],[]
>
> This is really nice.  I think the only major modification I'd make is
> to use a collections.deque() instead of lists here:
>
>   trues, falses = collections.deque(), collections.deque()
>
> as I seem to recall that list.pop(0) has some performance issues if
> it gets long, while the deque is optimized for fast (O(1)?) push/pop
> on either end.

Sure. If it's that good I might submit it to more-itertools... heh.

ChrisA

Back to comp.lang.python | Previous | NextPrevious in thread | Next in thread | Find similar | Unroll thread


Thread

Split a list into two parts based on a filter? roy@panix.com (Roy Smith) - 2013-06-10 16:34 -0400
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 08:50 +1000
  Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 00:50 +0200
    Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 00:11 -0400
      Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:27 +0300
        Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:33 -0400
          Re: Split a list into two parts based on a filter? Phil Connell <pconnell@gmail.com> - 2013-06-12 07:32 +0100
            Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-12 07:39 -0400
              Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 12:51 +0100
              Re: Split a list into two parts based on a filter? Jussi Piitulainen <jpiitula@ling.helsinki.fi> - 2013-06-12 15:06 +0300
              Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:07 -0400
          Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-12 19:28 +0300
          Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 17:57 +0100
          Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:47 -0400
          Re: Split a list into two parts based on a filter? Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-06-13 10:43 +0100
  Re: Split a list into two parts based on a filter? Chris Rebert <clp2@rebertia.com> - 2013-06-10 16:03 -0700
  Re: Split a list into two parts based on a filter? Tim Chase <python.list@tim.thechases.com> - 2013-06-10 18:10 -0500
  Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 00:08 +0100
    Re: Split a list into two parts based on a filter? alex23 <wuwei23@gmail.com> - 2013-06-11 17:44 -0700
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 09:12 +1000
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 02:11 +0200
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 08:43 +0200
  Re: Split a list into two parts based on a filter? Jonas Geiregat <jonas@geiregat.org> - 2013-06-11 08:47 +0200
  Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 14:48 +0100
    Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 09:37 -0700
      Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 18:05 +0100
        Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 10:23 -0700
          Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:37 +1000
            Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 11:13 -0700
          Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 19:05 +0100
  Re: Split a list into two parts based on a filter? Joshua Landau <joshua.landau.ws@gmail.com> - 2013-06-11 15:22 +0100
  Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:28 +0300
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:28 +1000
    Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:12 -0400
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:13 +0200
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:18 +0200
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 04:27 +1000
  Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 22:22 +0200

csiph-web