Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > comp.lang.python > #40343

Re: Sorting (deeply) nested lists

Show all headers | View raw

mamboknave@gmail.com wrote:

> I cannot resolve this on my own. Need help, please...
> 
> nestedTuples = [
> [ (L0t0e0, L0t0e1, L0t0e2), (L0t1e0, 2, L0t1e2), (L0t2e0, L0t2e1, L0t2e2)
> [ ], (L1t0e0, L1t0e1, L1t0e2), (L1t1e0, 0, L1t1e2), (L1t2e0, L1t2e1,
> [ L1t2e2) ], (L2t0e0, L2t0e1, L2t0e2), (L2t1e0, 1, L2t1e2), (L2t2e0,
> [ L2t2e1, L2t2e2) ] ]
> 
> With LNtXeY I mean the element Y in the tuple X of the list N.
> 
> How can I sort nestedTuples by, say, the 2nd element in the 2nd tuple of
> each list?

def getkey(item):
    return item[1][1]
namedTuples.sort(key=getkey)

You can also write this as

namedTuples.sort(key=lambda item: item[1][1])

> The above should get sorted as :
> 
> nestedTuples = [
> [ (L1t0e0, L1t0e1, L1t0e2), (L1t1e0, 0, L1t1e2), (L1t2e0, L1t2e1, L1t2e2)
> [ ], (L2t0e0, L2t0e1, L2t0e2), (L2t1e0, 1, L2t1e2), (L2t2e0, L2t2e1,
> [ L2t2e2) ], (L0t0e0, L0t0e1, L0t0e2), (L0t1e0, 2, L0t1e2), (L0t2e0,
> [ L0t2e1, L0t2e2) ] ]

Back to comp.lang.python | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread

Thread

Sorting (deeply) nested lists mamboknave@gmail.com - 2013-03-02 09:18 -0800
  Re: Sorting (deeply) nested lists Peter Otten <__peter__@web.de> - 2013-03-02 18:36 +0100
    Re: Sorting (deeply) nested lists mamboknave@gmail.com - 2013-03-02 09:49 -0800
    Re: Sorting (deeply) nested lists mamboknave@gmail.com - 2013-03-02 09:49 -0800

csiph-web