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Re: Obtaining a full path name from file

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Date Wed, 25 May 2011 07:05:16 -0400
From Dave Angel <davea@ieee.org>
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To RVince <rvince99@gmail.com>
Subject Re: Obtaining a full path name from file
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On 01/-10/-28163 02:59 PM, RVince wrote:
> s = "C:\AciiCsv\Gravity_Test_data\A.csv"
> f = open(s,"r")
>
> How do I obtain the full pathname given the File, f? (which should
> equal "C:\AciiCsv\Gravity_Test_data"). I've tried all sorts of stuff
> and am just not finding it. Any help greatly appreciated !
>

I saw lots of responses, but I don't think anybody pointed out that the 
filename is probably invalid.  This particular string will work, but if 
you have a directory that starts with a T or an N, you may get some 
surprises.  The backslash is treated specially in a literal string.

When building a Windows directory name in a literal string, you 
generally need to do one of three things:

1) use raw literals
2) double the backslash
3) use a forward slash

DaveA

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Thread

Obtaining a full path name from file RVince <rvince99@gmail.com> - 2011-05-24 08:36 -0700
  Re: Obtaining a full path name from file Tim Golden <mail@timgolden.me.uk> - 2011-05-24 16:52 +0100
    Re: Obtaining a full path name from file RVince <rvince99@gmail.com> - 2011-05-24 09:04 -0700
      Re: Obtaining a full path name from file Chris Angelico <rosuav@gmail.com> - 2011-05-25 02:08 +1000
      Re: Obtaining a full path name from file Tim Golden <mail@timgolden.me.uk> - 2011-05-24 17:10 +0100
      Re: Obtaining a full path name from file Jean-Michel Pichavant <jeanmichel@sequans.com> - 2011-05-24 18:13 +0200
    Re: Obtaining a full path name from file Mel <mwilson@the-wire.com> - 2011-05-24 12:04 -0400
  Re: Obtaining a full path name from file Ulrich Eckhardt <ulrich.eckhardt@dominolaser.com> - 2011-05-25 08:36 +0200
    Re: Obtaining a full path name from file Tim Golden <mail@timgolden.me.uk> - 2011-05-25 08:29 +0100
  Re: Obtaining a full path name from file Dave Angel <davea@ieee.org> - 2011-05-25 07:05 -0400

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