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Date: Wed, 25 May 2011 07:05:16 -0400
From: Dave Angel <davea@ieee.org>
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To: RVince <rvince99@gmail.com>
Subject: Re: Obtaining a full path name from file
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On 01/-10/-28163 02:59 PM, RVince wrote:
> s = "C:\AciiCsv\Gravity_Test_data\A.csv"
> f = open(s,"r")
>
> How do I obtain the full pathname given the File, f? (which should
> equal "C:\AciiCsv\Gravity_Test_data"). I've tried all sorts of stuff
> and am just not finding it. Any help greatly appreciated !
>

I saw lots of responses, but I don't think anybody pointed out that the 
filename is probably invalid.  This particular string will work, but if 
you have a directory that starts with a T or an N, you may get some 
surprises.  The backslash is treated specially in a literal string.

When building a Windows directory name in a literal string, you 
generally need to do one of three things:

1) use raw literals
2) double the backslash
3) use a forward slash

DaveA