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Groups > comp.lang.python > #83698
| From | Peter Otten <__peter__@web.de> |
|---|---|
| Subject | Re: what would be the regular expression for null byte present in a string |
| Date | 2015-01-13 15:41 +0100 |
| Organization | None |
| References | <39F9E8A5546B9448A82E55FBEBE3EC450BD029A5@SACMBXIP03.sdcorp.global.sandisk.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.17677.1421160126.18130.python-list@python.org> (permalink) |
Shambhu Rajak wrote: > I have a string that I get as an output of a command as: > '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n' > > I want to fetch '10232ae8944a' from the above string. > > I want to find a re pattern that could replace all the \x01..\x0z to be > replace by empty string '', so that I can get the desired portion of > string > > Can anyone help me with a working regex for it. I think you want the str.tranlate() method rather than a regex. Assuming you are using Python 2: >>> delenda = "".join(map(chr, range(32))) >>> identity = "".join(map(chr, range(256))) >>> '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n'.translate(identity, delenda) '10232ae8944a' With Python3: >>> mapping = dict.fromkeys(range(32)) >>> '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n'.translate(mapping) '10232ae8944a'
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Re: what would be the regular expression for null byte present in a string Peter Otten <__peter__@web.de> - 2015-01-13 15:41 +0100
Re: what would be the regular expression for null byte present in a string Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-01-14 14:52 +0100
Re: what would be the regular expression for null byte present in a string Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-01-14 15:11 +0100
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