Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!newsfeed.xs4all.nl!newsfeed3a.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.000 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'output': 0.05; 'string.': 0.05; "'',": 0.07; 'subject:would': 0.07; 'string': 0.09; 'assuming': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'subject:string': 0.09; 'python': 0.11; 'fetch': 0.16; 'received:80.91.229.3': 0.16; 'received:dip0.t-ipconnect.de': 0.16; 'received:plane.gmane.org': 0.16; 'received:t-ipconnect.de': 0.16; 'shambhu': 0.16; 'subject:expression': 0.16; 'subject:regular': 0.16; 'wrote:': 0.18; 'command': 0.22; '>>>': 0.22; 'portion': 0.22; 'header:User-Agent:1': 0.23; 'replace': 0.24; 'header:X-Complaints-To:1': 0.27; "skip:' 10": 0.31; 'subject:what': 0.31; 'anyone': 0.31; 'skip:d 20': 0.34; 'subject:the': 0.34; 'could': 0.34; 'method': 0.36; 'mapping': 0.38; 'to:addr:python-list': 0.38; 'rather': 0.38; 'to:addr:python.org': 0.39; 'received:org': 0.40; 'as:': 0.81; "skip:' 110": 0.84 X-Injected-Via-Gmane: http://gmane.org/ To: python-list@python.org From: Peter Otten <__peter__@web.de> Subject: Re: what would be the regular expression for null byte present in a string Date: Tue, 13 Jan 2015 15:41:51 +0100 Organization: None References: <39F9E8A5546B9448A82E55FBEBE3EC450BD029A5@SACMBXIP03.sdcorp.global.sandisk.com> Mime-Version: 1.0 Content-Type: text/plain; charset="ISO-8859-1" Content-Transfer-Encoding: 7Bit X-Gmane-NNTP-Posting-Host: p57bd9983.dip0.t-ipconnect.de User-Agent: KNode/4.13.3 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 33 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1421160126 news.xs4all.nl 2961 [2001:888:2000:d::a6]:60869 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:83698 Shambhu Rajak wrote: > I have a string that I get as an output of a command as: > '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n' > > I want to fetch '10232ae8944a' from the above string. > > I want to find a re pattern that could replace all the \x01..\x0z to be > replace by empty string '', so that I can get the desired portion of > string > > Can anyone help me with a working regex for it. I think you want the str.tranlate() method rather than a regex. Assuming you are using Python 2: >>> delenda = "".join(map(chr, range(32))) >>> identity = "".join(map(chr, range(256))) >>> '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n'.translate(identity, delenda) '10232ae8944a' With Python3: >>> mapping = dict.fromkeys(range(32)) >>> '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n'.translate(mapping) '10232ae8944a'