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Re: creating an artificial "last element" in sort list

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Date Fri, 28 Sep 2012 17:59:48 -0700 (PDT)
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> f = filter(lambda s: s == a[-1], a)

That line's assuming that the last element may also be found in arbitrary locations in the list. If it's guaranteed that they're all contiguous at the upper bounds, I'd just walk the list backwards until I found one that wasn't matching rather than filtering.

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creating an artificial "last element" in sort list dave <davidreynon@gmail.com> - 2012-09-28 16:39 -0700
  Re: creating an artificial "last element" in sort list Ian Kelly <ian.g.kelly@gmail.com> - 2012-09-28 17:45 -0600
    Re: creating an artificial "last element" in sort list dave <davidreynon@gmail.com> - 2012-09-28 16:51 -0700
      Re: creating an artificial "last element" in sort list 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-28 17:24 -0700
      Re: creating an artificial "last element" in sort list 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-28 17:24 -0700
      Re: creating an artificial "last element" in sort list Demian Brecht <demianbrecht@gmail.com> - 2012-09-28 17:32 -0700
        Re: creating an artificial "last element" in sort list Demian Brecht <demianbrecht@gmail.com> - 2012-09-28 17:59 -0700
          Re: creating an artificial "last element" in sort list Ian Kelly <ian.g.kelly@gmail.com> - 2012-09-28 21:29 -0600
        Re: creating an artificial "last element" in sort list Demian Brecht <demianbrecht@gmail.com> - 2012-09-28 17:59 -0700
      Re: creating an artificial "last element" in sort list duncan smith <buzzard@invalid.invalid> - 2012-09-29 02:19 +0100
    Re: creating an artificial "last element" in sort list dave <davidreynon@gmail.com> - 2012-09-28 16:51 -0700
  Re: creating an artificial "last element" in sort list Paul Rubin <no.email@nospam.invalid> - 2012-09-28 18:42 -0700
  Re: creating an artificial "last element" in sort list Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2012-09-29 02:05 +0000

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