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| From | Ian Kelly <ian.g.kelly@gmail.com> |
| Date | Wed, 26 Sep 2012 15:39:32 -0600 |
| Subject | Re: using "*" to make a list of lists with repeated (and independent) elements |
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On Wed, Sep 26, 2012 at 3:20 PM, TP <TP@frenoespam.fr.invalid> wrote: > Hi everybody, > > I have tried, naively, to do the following, so as to make lists quickly: > >>>> a=[0]*2 >>>> a > [0, 0] >>>> a[0]=3 >>>> a > [3, 0] > > All is working fine, so I extended the technique to do: > >>>> a=[[0]*3]*2 >>>> a > [[0, 0, 0], [0, 0, 0]] >>>> a[0][0]=2 >>>> a > [[2, 0, 0], [2, 0, 0]] > > The behavior is no more expected! > The reason is probably that in the first case, 0 is an integer, not a list, > so Python copies two elements that are independent. > In the second case, the elements are [0,0,0], which is a list; when Python > copies a list, he copies in fact the *pointer* to the list, such that we > obtain this apparently strange behavior. Mostly correct. When you do [foo] * 3 it extends the list with the *same objects* no matter what type they are. In the case of integers, it doesn't matter that it's the same objects, because integers are immutable. Lists are mutable, however, and so it becomes apparent that the same objects are repeated when you try to modify one of the lists. > In these conditions, how to make this list [[0,0,0],[0,0,0]] with "*" > without this behavior? Use a list comprehension: a = [[0] * 3 for _ in range(2)] This way the expression `[0] * 3` is re-evaluated at each position in the outer list, rather than evaluated just once and then copied.
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using "*" to make a list of lists with repeated (and independent) elements TP <TP@frenoespam.fr.invalid> - 2012-09-26 23:20 +0200
Re: using "*" to make a list of lists with repeated (and independent) elements Ian Kelly <ian.g.kelly@gmail.com> - 2012-09-26 15:39 -0600
Re: using "*" to make a list of lists with repeated (and independent) elements Paul Rubin <no.email@nospam.invalid> - 2012-09-26 14:43 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 15:07 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 15:28 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements Tim Chase <python.list@tim.thechases.com> - 2012-09-26 17:45 -0500
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 15:53 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 15:53 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-27 14:24 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-27 14:24 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements Ramchandra Apte <maniandram01@gmail.com> - 2012-09-29 06:46 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-29 10:01 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements Ian Kelly <ian.g.kelly@gmail.com> - 2012-09-29 11:18 -0600
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-29 11:50 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-29 11:50 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements Chris Angelico <rosuav@gmail.com> - 2012-09-30 03:41 +1000
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-29 10:01 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements Ramchandra Apte <maniandram01@gmail.com> - 2012-09-29 06:46 -0700
Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 14:45 -0700
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