Re: using "*" to make a list of lists with repeated (and independent) elements

References	(2 earlier) <f7dd2519-4e27-4905-805e-1ecc0b06b06f@googlegroups.com> <4657ccef-b910-4781-9ea8-005b4e15f219@googlegroups.com> <mailman.1461.1348699454.27098.python-list@python.org> <98034dee-0108-4099-bbdd-82f90e96d383@googlegroups.com> <b336c631-f197-47ca-bd71-48cda7f1a755@googlegroups.com>
From	Ian Kelly <ian.g.kelly@gmail.com>
Date	2012-09-29 11:18 -0600
Subject	Re: using "*" to make a list of lists with repeated (and independent) elements
Newsgroups	comp.lang.python
Message-ID	<mailman.1643.1348939161.27098.python-list@python.org> (permalink)

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On Sat, Sep 29, 2012 at 11:01 AM, 88888 Dihedral
<dihedral88888@googlemail.com> wrote:
>
> Don't you get it why I avoided the lambda one liner as a functon.
>
> I prefer the def way with a name chosen.

Certainly, but the Bresenham line algorithm is O(n), which is why it
is so superior to quicksort that is O(n log n).  Of course you might
try the Capo Ferro optimization, but I find that Thibault cancels out
Capo Ferro, don't you?

Thread

using "*" to make a list of lists with repeated (and independent) elements TP <TP@frenoespam.fr.invalid> - 2012-09-26 23:20 +0200
  Re: using "*" to make a list of lists with repeated (and independent) elements Ian Kelly <ian.g.kelly@gmail.com> - 2012-09-26 15:39 -0600
  Re: using "*" to make a list of lists with repeated (and independent) elements Paul Rubin <no.email@nospam.invalid> - 2012-09-26 14:43 -0700
    Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 15:07 -0700
      Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 15:28 -0700
        Re: using "*" to make a list of lists with repeated (and independent) elements Tim Chase <python.list@tim.thechases.com> - 2012-09-26 17:45 -0500
          Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 15:53 -0700
          Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 15:53 -0700
          Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-27 14:24 -0700
          Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-27 14:24 -0700
          Re: using "*" to make a list of lists with repeated (and independent) elements Ramchandra Apte <maniandram01@gmail.com> - 2012-09-29 06:46 -0700
            Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-29 10:01 -0700
              Re: using "*" to make a list of lists with repeated (and independent) elements Ian Kelly <ian.g.kelly@gmail.com> - 2012-09-29 11:18 -0600
                Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-29 11:50 -0700
                Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-29 11:50 -0700
              Re: using "*" to make a list of lists with repeated (and independent) elements Chris Angelico <rosuav@gmail.com> - 2012-09-30 03:41 +1000
            Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-29 10:01 -0700
          Re: using "*" to make a list of lists with repeated (and independent) elements Ramchandra Apte <maniandram01@gmail.com> - 2012-09-29 06:46 -0700
  Re: using "*" to make a list of lists with repeated (and independent) elements 88888 Dihedral <dihedral88888@googlemail.com> - 2012-09-26 14:45 -0700

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