Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.lang.python > #44697
| Date | 2013-05-04 01:51 +0100 |
|---|---|
| From | MRAB <python@mrabarnett.plus.com> |
| Subject | Re: Collision of Two Rect |
| References | <9083ecbc-5666-41aa-aacb-3f08f062feed@googlegroups.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.1281.1367628664.3114.python-list@python.org> (permalink) |
On 03/05/2013 23:23, Alex Gardner wrote:
> When rect A collides with rect B they stick when I am wanting A to bounce off of B. I have tried different methods, but none seem to work. My source is here: http://pastebin.com/CBYPcubL
>
> The collision code itself is below:
> ------
> # Bounce off of the paddle
> if paddle_rect.colliderect(ball_rect):
> y_vel*=-1
> x_vel*=-1
>
Apart from the other comments, I'm not sure about this line:
y_vel = (math.fabs(2 - x_vel)**2) ** .5
Firstly, instead of math.fabs you could use abs:
y_vel = (abs(2 - x_vel)**2) ** .5
Then again, you're squaring the result, and the square of (2 - x_vel)
will always be positive anyway:
y_vel = ((2 - x_vel)**2) ** .5
You're also calculating getting the square root, for which math.sqrt
would be simpler:
y_vel = math.sqrt((2 - x_vel)**2)
Then again, you're calculating the square root of a squared number, so
you might as well just write:
y_vel = abs(2 - x_vel)
Back to comp.lang.python | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread
Collision of Two Rect Alex Gardner <agardner210@gmail.com> - 2013-05-03 15:23 -0700 Re: Collision of Two Rect Ian Kelly <ian.g.kelly@gmail.com> - 2013-05-03 17:42 -0600 Re: Collision of Two Rect MRAB <python@mrabarnett.plus.com> - 2013-05-04 01:51 +0100 Re: Collision of Two Rect Tim Roberts <timr@probo.com> - 2013-05-04 22:28 -0700 Re: Collision of Two Rect Joshua Landau <joshua.landau.ws@gmail.com> - 2013-05-06 17:38 +0100 Re: Collision of Two Rect Ian Kelly <ian.g.kelly@gmail.com> - 2013-05-06 14:18 -0600
csiph-web