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| From | Terry Reedy <tjreedy@udel.edu> |
| Subject | Re: Fibonacci series recursion error |
| Date | Sun, 01 May 2011 22:30:02 -0400 |
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On 5/1/2011 7:16 PM, BartC wrote: > Yes, it generates lots of calls. > > About 22000 for fib(20), and 330 million for fib(40). Using the standard double recursion implementation of fib, ncf(n) (number of calls to fib() for fib(n)) requires ncf(n-2) + ncf(n+1) + 1 calls. The +1 is for the call to fib(n) itself). So it grows a bit faster than fib(n). Fib(n) is actually calculated as the sum of fib(n) 1s: 1+1+1....+1 fib(n) times as 1 is the only non-0 base case and there is nothing else added or multiplied in non-base cases. To put it another way, there are fib(n) leaf nodes labeled 1 in the unbalanced tree generated by the recursion. -- Terry Jan Reedy
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Re: Fibonacci series recursion error Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-04-30 07:18 +0000
Re: Fibonacci series recursion error "BartC" <bc@freeuk.com> - 2011-05-02 00:16 +0100
Re: Fibonacci series recursion error Terry Reedy <tjreedy@udel.edu> - 2011-05-01 22:30 -0400
Re: Fibonacci series recursion error rusi <rustompmody@gmail.com> - 2011-05-02 01:27 -0700
Re: Fibonacci series recursion error Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-05-02 08:56 +0000
Re: Fibonacci series recursion error Hans Georg Schaathun <hg@schaathun.net> - 2011-05-02 10:53 +0100
Re: Fibonacci series recursion error rusi <rustompmody@gmail.com> - 2011-05-02 03:40 -0700
Re: Fibonacci series recursion error Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-05-02 16:24 +0000
Re: Fibonacci series recursion error Mark Dickinson <dickinsm@gmail.com> - 2011-05-02 14:18 -0700
Re: Fibonacci series recursion error Chris Angelico <rosuav@gmail.com> - 2011-05-02 19:03 +1000
Re: Fibonacci series recursion error Gregory Ewing <greg.ewing@canterbury.ac.nz> - 2011-05-05 14:35 +1200
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