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Re: CriteriaQuery and JPA

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Il 07/09/2011 20:02, Lew ha scritto:

> Read the Javadocs for 'Root#get(String attributeName)'.  You gave a 'null' attribute name, and what you tried to do wasn't giving an attribute *name*, but an attribute *value*.

Ok, I try to remake my question.
My class has a field named 'username':

public MyClass{
     public String username;
}

I have to create a where clause that check if this field is equal to a 
constant value:
WHERE username = "test"

I understand that Root#get(String attributeName) give to me the 
attribute name (and not the attribute value), so how can i put a 
constant value inside the clause?

filter.where(criteriaBuilder.equal(from.get("username"),"test"));

with this code i would expect a where clause like the above. Instead i 
have the null value : WHERE username = ?

Sorry but I'm new to JPA

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CriteriaQuery and JPA Lele <lamia@mail.lcom> - 2011-09-07 15:15 +0200
  Re: CriteriaQuery and JPA Lew <lewbloch@gmail.com> - 2011-09-07 11:02 -0700
    Re: CriteriaQuery and JPA Lele <lele@lele.com> - 2011-09-08 09:48 +0200
    Re: CriteriaQuery and JPA Lele <lelel@lele.com> - 2011-09-08 15:03 +0200
      Re: CriteriaQuery and JPA markspace <-@.> - 2011-09-08 06:39 -0700
        Re: CriteriaQuery and JPA Lele <lelel@lele.com> - 2011-09-08 16:53 +0200
          Re: CriteriaQuery and JPA Lew <lewbloch@gmail.com> - 2011-09-08 09:05 -0700

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