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CriteriaQuery and JPA

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Hi.

I'm trying to make some examples of query using CriteriaQuery.

For now i'm trying to do something like that:

@Entity
@Table(name = "USERS")
public class ClassTest {
     public ClassTrueAuth(){
     this.username = "test";
     }

     @Id
     @Column(name="testfield")
     public boolean testField ;

     @Column(name="username")
     public String username;
}

and inside my code:

ClassTest cta = new ClassTest();

CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery cq = criteriaBuilder.createQuery(ClassTest.class);
Root<ClassTest> from = cq.from(ClassTest.class);
cq.select(from);
Predicate p = criteriaBuilder.equal(from.get(cta.username),"test");
cq.where(p);
TypedQuery<ClassTest> q = entityManager.createQuery(cq);
List<ClassTest> result = q.getResultList();

This give to me a NullPointerException... How to check if a string field 
is equal to a constant?


I tried to make another field in TestClass:
@Column(name="test")
public String test = "test";

and retry the same code above. The query string printed in console is:

select classtest0_.testfield as testfield35_, classtest0_.username as 
username35_, classtest0_.test as test36_ from USERS classtruea0_ where 
classtruea0_.test=?

and 'result' is empty... Why where clause is test=? instead of 
username=test ?

Please help me!

Thank you so much!

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CriteriaQuery and JPA Lele <lamia@mail.lcom> - 2011-09-07 15:15 +0200
  Re: CriteriaQuery and JPA Lew <lewbloch@gmail.com> - 2011-09-07 11:02 -0700
    Re: CriteriaQuery and JPA Lele <lele@lele.com> - 2011-09-08 09:48 +0200
    Re: CriteriaQuery and JPA Lele <lelel@lele.com> - 2011-09-08 15:03 +0200
      Re: CriteriaQuery and JPA markspace <-@.> - 2011-09-08 06:39 -0700
        Re: CriteriaQuery and JPA Lele <lelel@lele.com> - 2011-09-08 16:53 +0200
          Re: CriteriaQuery and JPA Lew <lewbloch@gmail.com> - 2011-09-08 09:05 -0700

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