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| References | <CAGGBd_pd9SA7SczanGARFr-+Z9SxP9Mkhfo-RivpcJLrnuexng@mail.gmail.com> <851th2t05t.fsf@benfinney.id.au> <CAGGBd_qaNC38Yg0u_b8+qBAckq6FRTZMxbWwuzV=MUYE_=ZzDw@mail.gmail.com> <mailman.3.1435107726.3674.python-list@python.org> <87a8vpykwq.fsf@nightsong.com> |
|---|---|
| From | Ian Kelly <ian.g.kelly@gmail.com> |
| Date | 2015-06-24 00:50 -0600 |
| Subject | Re: Looking up a dictionary _key_ by key? |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.7.1435128694.3674.python-list@python.org> (permalink) |
On Tue, Jun 23, 2015 at 7:06 PM, Paul Rubin <no.email@nospam.invalid> wrote: > Chris Angelico <rosuav@gmail.com> writes: >>> Would I have to do an O(n) search to find my key? >> Iterate over it - it's an iterable view in Py3 - and compare. > > I think the question was whether the O(n) search could be avoided, not > how to do it. I don't see a way to avoid it. There is fundamental > brokenness in having unequal objects compare as equal, and the breakage > messes up the dictionary when those objects are used as keys. I don't think that it's fundamentally broken. A simple example would be the int 3, vs. the float 3, vs. the Decimal 3. All of them compare equal to one another, but they are distinct values, and sometimes it might be useful to be able to determine which one is actually a key in the dict.
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Re: Looking up a dictionary _key_ by key? Chris Angelico <rosuav@gmail.com> - 2015-06-24 11:02 +1000
Re: Looking up a dictionary _key_ by key? Paul Rubin <no.email@nospam.invalid> - 2015-06-23 18:06 -0700
Re: Looking up a dictionary _key_ by key? Ian Kelly <ian.g.kelly@gmail.com> - 2015-06-24 00:50 -0600
Re: Looking up a dictionary _key_ by key? Marko Rauhamaa <marko@pacujo.net> - 2015-06-24 09:55 +0300
Re: Looking up a dictionary _key_ by key? Laura Creighton <lac@openend.se> - 2015-07-05 08:25 +0200
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