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Groups > comp.lang.python > #63934

Re: Printer list value problem

From Mark Lawrence <breamoreboy@yahoo.co.uk>
Subject Re: Printer list value problem
Date 2014-01-14 20:03 +0000
References <6139406d-9ccc-41b2-8aa8-7f6fd2431366@googlegroups.com> <mailman.5470.1389727971.18130.python-list@python.org> <75028f66-b36c-4b1d-b055-3beb05b66f8c@googlegroups.com>
Newsgroups comp.lang.python
Message-ID <mailman.5474.1389729800.18130.python-list@python.org> (permalink)

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On 14/01/2014 19:54, Mike wrote:
> El martes, 14 de enero de 2014 16:32:49 UTC-3, MRAB  escribió:
>> On 2014-01-14 19:24, Mike wrote:
>>
>>> Hello,
>>
>>> I confudsed,need printer the value of list (this is reaer from csv) . The reader is ok, but my problem is in the print moment because printer only the last value. For example my csv is:
>>
>>>
>>
>>> [........]
>>
>>> user1@example.com;user1;lastName;Name
>>
>>> user2@example.com;user2;lastName;Name
>>
>>> [........]
>>
>>>
>>
>>> But when execute the script I view the print is only the last user
>>
>>>
>>
>>> [........]
>>
>>> ca user2@example.com displayName 'user2' sn 'lastName' cn 'Name'
>>
>>> [........]
>>
>>>
>>
>>> And I need the next printer
>>
>>>
>>
>>> [........]
>>
>>> ca user1@example.com displayName 'User1' sn ''lastName" cn 'Name'
>>
>>> ca user1@example.com displayName 'User2' sn ''lastName" cn 'Name'
>>
>>> [........]
>>
>>>
>>
>>> My script is
>>
>>>
>>
>>> [........]
>>
>>> #!/usr/bin/python
>>
>>> import csv
>>
>>> with open ('users.csv', 'rb') as f:
>>
>>>
>>
>>>           reader = csv.reader (f, delimiter=';' ) #delimiter tabulador
>>
>>>           for row in reader:
>>
>>>
>>
>>>                   mail     = row [0]
>>
>>>                   name     = row [3]
>>
>>>                   lastname = row [2]
>>
>>>
>>
>>
>>
>> This line is indented the same amount as the 'for' loop, which means
>>
>> that it will be executed after the loop has finished.
>>
>>
>>
>>>           print "ma {} displayName '{}' sn '{}'".format(mail,name,lastname)
>>
>>>
>>
>> You don't need to close the file here because the 'with' statement will
>>
>> do that for you.
>>
>>
>>
>>> f.close()
>>
>>> [........]
>>
>>>
>>
>>>
>>
>>> Thanks.
>>
>>>
>
> Hello MRAB,
> I remove the "f.close" and after execute the script but still i have the same result (print the last row)
>
> Thanks
>

Your print statement needs to be inside the for loop, you currently have 
it after the loop has finished.

Would you also please read and action this 
https://wiki.python.org/moin/GoogleGroupsPython to prevent us seeing the 
double line spacing above, thanks.

-- 
My fellow Pythonistas, ask not what our language can do for you, ask 
what you can do for our language.

Mark Lawrence

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Thread

Printer list value problem Mike <miguelcoam@gmail.com> - 2014-01-14 11:24 -0800
  Re: Printer list value problem MRAB <python@mrabarnett.plus.com> - 2014-01-14 19:32 +0000
    Re: Printer list value problem Mike <miguelcoam@gmail.com> - 2014-01-14 11:54 -0800
      Re: Printer list value problem Mark Lawrence <breamoreboy@yahoo.co.uk> - 2014-01-14 20:03 +0000
  Re: Printer list value problem Tim Chase <python.list@tim.thechases.com> - 2014-01-14 13:38 -0600

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