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Groups > comp.lang.python > #41613

Re: Test a list

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On 2013-03-20 11:15, Ana Dionísio wrote:
> t= [3,5,6,7,10,14,17,21]
> 
> Basically I want to print Test 1 when i is equal to an element of
> the list "t" and print Test 2 when i is not equal:
> 
> while i<=25:
>     if i==t[]:
>        print "Test1"
>     else:
>        print "Test2"
> 
> What is missing here for this script work?

Well, your code never increments "i", so it will loop forever; you
also don't subscript "t" with anything, so you have invalid syntax
there; you also don't have any values in the list that actually match
their 0-indexed offset, so even if your code was correct, it would
still (correctly) return Test2 for everything.

This sounds a bit like homework, but the Pythonic way would likely
iterate over the data and its enumeration:

  for index, value in enumerate(t):
    if index == value: # compare index & value accordingly
     ...

If you need to have the index start at 1 (or some other value)
instead of 0, and you're running Python2.6+, you can pass the initial
index to enumerate().  Otherwise, you have to do the math in your
comparison.

-tkc

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Thread

Test a list Ana Dionísio <anadionisio257@gmail.com> - 2013-03-20 11:15 -0700
  Re: Test a list timothy crosley <timothy.crosley@gmail.com> - 2013-03-20 11:24 -0700
  Re: Test a list Joel Goldstick <joel.goldstick@gmail.com> - 2013-03-20 14:26 -0400
  Re: Test a list Tim Chase <python.list@tim.thechases.com> - 2013-03-20 13:36 -0500
  Re: Test a list Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-03-20 18:40 +0000
  Re: Test a list John Gordon <gordon@panix.com> - 2013-03-20 20:39 +0000

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