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| References | <CAEH=cXWXwOf6QnNur4V3HNBZ2i13gVnOiJDOOyCZs1Putc_mug@mail.gmail.com> <CAMZYqRRyrEGOmu_9OcUTLH7nZjNna=Z_XX_b4vHzf3ATxgehzw@mail.gmail.com> |
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| Date | 2013-03-07 09:34 +0000 |
| Subject | Re: iterating over a list as if it were a circular list |
| From | Sven <svenito@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.2999.1362648888.2939.python-list@python.org> (permalink) |
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On 7 March 2013 09:31, Chris Rebert <clp2@rebertia.com> wrote: > On Mar 7, 2013 1:24 AM, "Sven" <svenito@gmail.com> wrote: > > > > I was wondering what the best approach for the following might be. > > > > Say you have a list P of points and another list N of other items. You > can always assume that > > > > len(N) <= len(P) > > > > Now I would like to iterate over P and place one N at each point. > However if you run out of N I'd like to restart from N[0] and carry on > until all the points have been populated. > > Untested due to the late hour: > > import itertools > > for p, n in itertools.izip(P, itertools.cycle(N)): > # do whatever > I knew there was a more sensible way to do it. Thanks. -- ./Sven
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Re: iterating over a list as if it were a circular list Sven <svenito@gmail.com> - 2013-03-07 09:34 +0000
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