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Re: Pythonic way for retrieving value for a nested dictionary.

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On 03/05/2013 01:48 AM, Lowly Minion wrote:
> For a typical dict:
>
> i.e.
> d = { '1': 'a', '2', 'b' }
>
> I might use something like:
>
> d.get('1', None)
>
> To get the value of 1.
>
> What would be the most pythonic way of getting a nested value of a dictionary within a list:
>
> some_list = [{ 'item': { 'letter': 'b',
>                                    'word': 'bar' }},
>                      { 'item': { 'letter': 'c',
>                                    'word': 'charcoal' }}]
>
> Currently I am looping through the list as such:
>
> for item in some_list:
>    print item['item']['letter']
>
> One other method explored was:
> item.get('item').get('letter')
>
> Is a double get the best way? Doesn't seem right to me.
>
> Thank you in advance for your help
>


I'm not sure what the puzzle is.  Use [key] if you know the key exists, 
and use get( key, default) if you don't.  But be aware that if the first 
key doesn't exist, then the default had better be a dict (rather than 
something like None), or the second lookup will throw an exception, even 
if you use get.

One other possibility, depending on just what you're doing with the 
data, is to wrap it in a try/catch.

However, if you know exactly what the keys are, perhaps you should use a 
namedtuple instead of a dict.

-- 
DaveA

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Pythonic way for retrieving value for a nested dictionary. Lowly Minion <fruiz@twitter.com> - 2013-03-04 22:48 -0800
  Re: Pythonic way for retrieving value for a nested dictionary. Dave Angel <davea@davea.name> - 2013-03-05 02:20 -0500

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