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Groups > comp.lang.python > #32009

Re: Fast forward-backward (write-read)

Date 2012-10-24 09:05 +0200
From Virgil Stokes <vs@it.uu.se>
Subject Re: Fast forward-backward (write-read)
References <5086AA35.4000509@it.uu.se> <CA+vVgJV6feUL0gTPC==3fp3Wq8zvRXgoyhVaUYnZNtMfF8qpLw@mail.gmail.com> <CA+vVgJWnAThHhD4cUJzXLGdVojCNA1oV_qKYwa+7UsEqS=x7XQ@mail.gmail.com>
Newsgroups comp.lang.python
Message-ID <mailman.2732.1351062335.27098.python-list@python.org> (permalink)

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On 24-Oct-2012 00:36, David Hutto wrote:
>> Don't forget to use timeit for an average OS utilization.
>>
>> I'd suggest two list comprehensions for now, until I've reviewed it some more:
>>
>> forward =  ["%i = %s" % (i,chr(i)) for i in range(33,126)]
>> backward = ["%i = %s" % (i,chr(i)) for i in range(126,32,-1)]
>>
>> for var in forward:
>>          print var
>>
>> for var in backward:
>>          print var
>>
>> You could also use a dict, and iterate through a straight loop that
>> assigned a front and back to a dict_one =  {0 : [0.100], 1 : [1.99]}
>> and the iterate through the loop, and call the first or second in the
>> dict's var list for frontwards , or backwards calls.
>>
>>
>> But there might be faster implementations, depending on other
>> function's usage of certain lower level functions.
>>
> Missed the part about it being a file. Use:
>
> forward =  ["%i = %s" % (i,chr(i)) for i in range(33,126)]
> backward = ["%i = %s" % (i,chr(i)) for i in range(126,32,-1)]
>
> print forward,backward
Interesting approach for small data sets (or blocks from a much larger data set).

Thanks David :-)

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Re: Fast forward-backward (write-read) Virgil Stokes <vs@it.uu.se> - 2012-10-24 09:05 +0200

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