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Groups > comp.lang.python > #52688
| Date | 2013-08-19 07:32 -0500 |
|---|---|
| From | Anthony Papillion <papillion@gmail.com> |
| Subject | Re: Question about crypto |
| References | <52114329.2030801@gmail.com> <CANc-5UzS=1=Z132=ZEYr2k5Bjh7SwY2S40ohB7djSf5dEKibFg@mail.gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.27.1376915564.19984.python-list@python.org> (permalink) |
On 08/18/2013 05:29 PM, Skip Montanaro wrote: >> When I run the code above, I am told that the IV must be 16 bytes long. >> I'm assuming that the IV (I know that means "Initialization Vector") is >> either the key OR something else I can set. But I don't know how or what >> to do. > > Does this Stack Overflow thread help? It looks to me like you aren't > defining an initialization vector at all. > > http://stackoverflow.com/questions/14716338/pycrypto-how-does-the-initialization-vector-work Completely missed that Stack Overflow discussion. Thanks, Skip! That does help! Anthony
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Re: Question about crypto Anthony Papillion <papillion@gmail.com> - 2013-08-19 07:32 -0500
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