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Groups > comp.lang.python > #99728

Re: I can't understand re.sub

From Erik <python@lucidity.plus.com>
Newsgroups comp.lang.python
Subject Re: I can't understand re.sub
Date 2015-11-29 21:53 +0000
Message-ID <mailman.26.1448872519.14615.python-list@python.org> (permalink)
References <af27abe4-f81e-4d44-a504-c58d9e71986a@googlegroups.com>

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On 29/11/15 21:36, Mr Zaug wrote:
> I need to use re.sub to replace strings in a text file.

Do you? Is there any other way?

> result = re.sub(pattern, repl, string, count=0, flags=0);
>
> I think I understand that pattern is the regex I'm searching for and
> repl is the thing I want to substitute for whatever pattern finds but
> what is string?

Where do you think the function gets the string you want to transform from?

> This should be simple, right?

It is. And it could be even simpler if you don't bother with regexes at 
all (if your input is as fixed as you say it is):

 >>> foo = "foo bar baz spam CONTENT_PATH bar spam"
 >>> ' Substitute '.join(foo.split(' CONTENT_PATH ', 1))
'foo bar baz spam Substitute bar spam'
 >>>

E.

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Thread

I can't understand re.sub Mr Zaug <matthew.herzog@gmail.com> - 2015-11-29 13:36 -0800
  Re: I can't understand re.sub Denis McMahon <denismfmcmahon@gmail.com> - 2015-11-29 22:01 +0000
    Re: I can't understand re.sub Mr Zaug <matthew.herzog@gmail.com> - 2015-11-29 17:20 -0800
  Re: I can't understand re.sub Rick Johnson <rantingrickjohnson@gmail.com> - 2015-11-29 17:12 -0800
    Re: I can't understand re.sub Mr Zaug <matthew.herzog@gmail.com> - 2015-11-29 17:24 -0800
  Re: I can't understand re.sub Erik <python@lucidity.plus.com> - 2015-11-29 21:53 +0000
    Re: I can't understand re.sub Jussi Piitulainen <harvesting@is.invalid> - 2015-11-30 10:51 +0200
      Re: I can't understand re.sub Erik <python@lucidity.plus.com> - 2015-12-01 01:26 +0000
        Re: I can't understand re.sub Jussi Piitulainen <harvesting@is.invalid> - 2015-12-01 07:28 +0200
          Re: I can't understand re.sub Erik <python@lucidity.plus.com> - 2015-12-01 21:31 +0000

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