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Re: $OPTIND varibale value is different from sh

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Op 20-06-18 om 17:45 schreef Ilkka Virta:
> $ for sh in dash 'busybox sh' bash ksh93 zsh ; do printf "%-10s: " 
> "$sh"; $sh -c 'while getopts abcd opt; do printf "$OPTIND  "; done; 
> printf "$OPTIND  "; shift $(($OPTIND - 1)); echo "$1" ' sh -a -bcd 
> hello; done
> dash      : 2  3  3  3  3  hello
> busybox sh: 2  3  3  3  3  hello
> bash      : 2  2  2  3  3  hello
> ksh93     : 2  2  2  3  3  hello
> zsh       : 1  2  2  2  3  hello

yash has interesting behaviour here. While other shells use an extra 
internal (i.e. not exposed to the shell language) state variable to keep 
track of parsing multiple options combined in a single argument, yash 
just adds that extra state value to OPTIND.

yash      : 1:2  2:2  2:3  2:4  3  hello

Which demonstrates quite well that the value of OPTIND in the middle of 
processing really should be considered unspecified, and that only the 
initial value (1) and the final value can be relied upon.

Relevant POSIX text:

http://pubs.opengroup.org/onlinepubs/9699919799/utilities/getopts.html#tag_20_54
| If the application sets OPTIND to the value 1, a new set of
| parameters can be used: either the current positional parameters or
| new arg values. Any other attempt to invoke getopts multiple times in
| a single shell execution environment with parameters (positional
| parameters or arg operands) that are not the same in all invocations,
| or with an OPTIND value modified to be a value other than 1, produces
| unspecified results.


- M.

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Re: $OPTIND varibale value is different from sh Martijn Dekker <martijn@inlv.org> - 2018-06-20 19:22 +0100

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