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Re: Python 3.X: nonlocal support in eval/exec?

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On 8/11/2011 3:19 AM, Paddy wrote:
> We can access nonlocal variables in a function, but if we were to eval/
> exec the function we cannot set up a nested stack of evironment dicts.
> We are limited to just two: global and local.

Right. That was and is Python's execution model.
Note that when you exec code, including a function call, the locals 
passed is the local context in which the code is executed. It is not the 
locals of any particular function called by the exec-ed code.

If you exec a function that is a closure, the closure or non-local 
objects come with the function. A 'stack of dicts' has nothing to do 
with how function and nested funcs operate.

-- 
Terry Jan Reedy

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Python 3.X: nonlocal support in eval/exec? Paddy <paddy3118@googlemail.com> - 2011-08-11 00:19 -0700
  Re: Python 3.X: nonlocal support in eval/exec? Terry Reedy <tjreedy@udel.edu> - 2011-08-11 03:48 -0400
    Re: Python 3.X: nonlocal support in eval/exec? Paddy <paddy3118@googlemail.com> - 2011-08-11 13:31 -0700

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