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Re: No word splitting for assignment-like expressions in compound assignment

From Ilkka Virta <itvirta@iki.fi>
Newsgroups gnu.bash.bug
Subject Re: No word splitting for assignment-like expressions in compound assignment
Date 2020-07-28 23:14 +0300
Message-ID <mailman.213.1595967312.2739.bug-bash@gnu.org> (permalink)
References <6614fa7668daf7f2b450e319a28b624c@ispras.ru> <58020735-2ddb-e1a4-a513-a09560876e87@case.edu> <071ced16-0537-133d-8c1b-f54fefac1e33@iki.fi>

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On 28.7. 17:22, Chet Ramey wrote:
> On 7/23/20 8:11 PM, Alexey Izbyshev wrote:
>> $ Z='a b'
>> $ A=(X=$Z)
>> $ declare -p A
>> declare -a A=([0]="X=a b")

> It's an assignment statement in a context where assignment statements are
> accepted (which is what makes it different from `echo X=$Z', for instance),
> but the lack of a subscript on the lhs makes it a special case. I'll take a
> look at the semantics here.

This is also a bit curious:

  $ b=( [123]={a,b,c}x )
  $ declare -p b
  declare -a b=([0]="[123]=ax" [1]="[123]=bx" [2]="[123]=cx")

It does seem to have a subscript on the LHS, but it didn't work as one.
To be in line with a plain scalar assignment, the braces should probably 
not be expanded here.


-- 
Ilkka Virta / itvirta@iki.fi

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Re: No word splitting for assignment-like expressions in compound assignment Ilkka Virta <itvirta@iki.fi> - 2020-07-28 23:14 +0300

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