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Groups > gnu.bash.bug > #16384
| From | Chet Ramey <chet.ramey@case.edu> |
|---|---|
| Newsgroups | gnu.bash.bug |
| Subject | Re: hash -l with empty hash table prints to stdout |
| Date | 2020-06-16 09:30 -0400 |
| Organization | ITS, Case Western Reserve University |
| Message-ID | <mailman.1976.1592314236.2541.bug-bash@gnu.org> (permalink) |
| References | <20200615204717.GB28118@jar> <bd77214b-2690-f5de-a814-108e5be8b6f1@case.edu> |
On 6/15/20 4:47 PM, beluro@web.de wrote: > Bash Version: 5.0 > Patch Level: 3 > Release Status: release > > Description: > `hash -l' is supposed to generate output that is reusable as input > (`help hash' says so, at least). In case the hash table is empty, a > string not re-usable as input is output to stdout. The exit code > indicates success in this case. The string being output is locale- > dependant (and therefore is hard to filter out in a work-around). It's an interesting question. An empty hash table is not an error condition, and doesn't result in a non-zero exit status, so output to stderr is not appropriate. You might want to temporarily enable posix mode, which suppresses the message. -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ``Ars longa, vita brevis'' - Hippocrates Chet Ramey, UTech, CWRU chet@case.edu http://tiswww.cwru.edu/~chet/
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Re: hash -l with empty hash table prints to stdout Chet Ramey <chet.ramey@case.edu> - 2020-06-16 09:30 -0400
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