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Groups > comp.lang.python > #45436
| Date | 2013-05-16 11:22 -0400 |
|---|---|
| From | Ned Batchelder <ned@nedbatchelder.com> |
| Subject | Re: spilt question |
| References | <d8c03de0-dc35-45e3-a6b2-2af39feb9e79@googlegroups.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.1761.1368717742.3114.python-list@python.org> (permalink) |
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On 5/16/2013 11:00 AM, loial wrote:
> I want to split a string so that I always return everything BEFORE the LAST underscore
>
> HELLO_xxxxxxxx.lst # should return HELLO
> HELLO_GOODBYE_xxxxxxxx.ls # should return HELLO_GOODBYE
>
> I have tried with rsplit but cannot get it to work.
>
> Any help appreciated
>
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rpartition('_')
('HELLO_GOODBYE', '_', 'xxxxxxxx.ls')
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit('_', 1)
['HELLO_GOODBYE', 'xxxxxxxx.ls']
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rpartition('_')[0]
'HELLO_GOODBYE'
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit('_', 1)[0]
'HELLO_GOODBYE'
For the future, getting help works better if you show what you tried,
and what it produced.
--Ned.
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spilt question loial <jldunn2000@gmail.com> - 2013-05-16 08:00 -0700 Re: spilt question Walter Hurry <walterhurry@lavabit.com> - 2013-05-16 15:10 +0000 Re: spilt question Fábio Santos <fabiosantosart@gmail.com> - 2013-05-16 16:14 +0100 Re: spilt question Chris Angelico <rosuav@gmail.com> - 2013-05-17 01:15 +1000 Re: spilt question Dave Angel <davea@davea.name> - 2013-05-16 11:20 -0400 Re: spilt question Tim Chase <python.list@tim.thechases.com> - 2013-05-16 10:23 -0500 Re: spilt question Ned Batchelder <ned@nedbatchelder.com> - 2013-05-16 11:22 -0400 Re: spilt question Dave Angel <davea@davea.name> - 2013-05-16 11:32 -0400
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