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Re: spilt question

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On Fri, May 17, 2013 at 1:00 AM, loial <jldunn2000@gmail.com> wrote:
> I want to split a string so that I always return everything BEFORE the LAST underscore
>
> HELLO_xxxxxxxx.lst         # should return HELLO
> HELLO_GOODBYE_xxxxxxxx.ls  # should return HELLO_GOODBYE
>
> I have tried with rsplit but cannot get it to work.
>
> Any help appreciated

Try with a limit:

>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit("_",1)
['HELLO_GOODBYE', 'xxxxxxxx.ls']
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit("_",1)[0]
'HELLO_GOODBYE'

You can easily get docs on it:

>>> help("".rsplit)
Help on built-in function rsplit:

rsplit(...)
    S.rsplit(sep=None, maxsplit=-1) -> list of strings

    Return a list of the words in S, using sep as the
    delimiter string, starting at the end of the string and
    working to the front.  If maxsplit is given, at most maxsplit
    splits are done. If sep is not specified, any whitespace string
    is a separator.

ChrisA

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spilt question loial <jldunn2000@gmail.com> - 2013-05-16 08:00 -0700
  Re: spilt question Walter Hurry <walterhurry@lavabit.com> - 2013-05-16 15:10 +0000
  Re: spilt question Fábio Santos <fabiosantosart@gmail.com> - 2013-05-16 16:14 +0100
  Re: spilt question Chris Angelico <rosuav@gmail.com> - 2013-05-17 01:15 +1000
  Re: spilt question Dave Angel <davea@davea.name> - 2013-05-16 11:20 -0400
  Re: spilt question Tim Chase <python.list@tim.thechases.com> - 2013-05-16 10:23 -0500
  Re: spilt question Ned Batchelder <ned@nedbatchelder.com> - 2013-05-16 11:22 -0400
  Re: spilt question Dave Angel <davea@davea.name> - 2013-05-16 11:32 -0400

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