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Groups > comp.lang.python > #5549
| Date | 2011-05-17 06:13 +0100 |
|---|---|
| From | Andy Baxter <highfellow@gmail.com> |
| Subject | indirect assignment question |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.1657.1305609210.9059.python-list@python.org> (permalink) |
Hi,
I have some lines of code which currently look like this:
self.window = self.wTree.get_widget("mainWindow")
self.outputToggleMenu = self.wTree.get_widget("menuitem_output_on")
self.outputToggleButton =
self.wTree.get_widget("button_toggle_output")
self.logView = self.wTree.get_widget("textview_log")
self.logScrollWindow = self.wTree.get_widget("scrolledwindow_log")
and I would like (for tidiness / compactness's sake) to replace them
with something like this:
widgetDic = {
"mainWindow": self.window,
"menuitem_output_on": self.outputToggleMenu,
"button_toggle_output": self.outputToggleButton,
"textview_log": self.logView,
"scrolledwindow_log": self.logScrollWindow
}
for key in widgetDic:
... set the variable in dic[key] to point to
self.wTree.get_widget(key) somehow
what I need is some kind of indirect assignment where I can assign to a
variable whose name is referenced in a dictionary value.
Is there a way of doing this in python?
thanks,
andy baxter
--
http://highfellow.org
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indirect assignment question Andy Baxter <highfellow@gmail.com> - 2011-05-17 06:13 +0100 Re: indirect assignment question Ben Finney <ben+python@benfinney.id.au> - 2011-05-17 16:01 +1000 Re: indirect assignment question Thomas Rachel <nutznetz-0c1b6768-bfa9-48d5-a470-7603bd3aa915@spamschutz.glglgl.de> - 2011-05-17 09:15 +0200
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