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Re: Pythonic way with more than one max possible

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On Tue, Jul 19, 2011 at 8:17 PM, CM <cmpython@gmail.com> wrote:
> I have three items in a dict, like this:
>
> the_dict = {'a':1, 'b':2, 'c':3}
>
> but the vals could be anything.  I want to configure something else
> based on the "winner" of such a dict, with these rules:
>
> 1. In this dict, if there is a UNIQUE max value, that's the winner.
> 2. If there are any TIES for max value, b is the winner by default.

Er, for (2), you mean b's /value/ is the winner, right?

> The problem for me, as I see it, is I don't know any elegant ways to
> do this in Python.  The max(dict) function doesn't distinguish between
> unique and non-unique maxes.  I could go through and test the various
> possibilities (to see if the max value had any matches in the other
> values), but, knowing Python, there is probably something close to
> "one way to do it".  Any suggestions?

# presumes at least 2 items
from heapq import nlargest
winner, runner_up = nlargest(2, the_dict.itervalues())
if winner == runner_up:
    winner = the_dict['b']

Cheers,
Chris
--
http://rebertia.com

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Thread

Pythonic way with more than one max possible CM <cmpython@gmail.com> - 2011-07-19 20:17 -0700
  Re: Pythonic way with more than one max possible Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-07-20 14:19 +1000
    Re: Pythonic way with more than one max possible Thomas Jollans <t@jollybox.de> - 2011-07-20 12:51 +0200
  Re: Pythonic way with more than one max possible Chris Rebert <clp2@rebertia.com> - 2011-07-19 21:33 -0700
  Re: Pythonic way with more than one max possible CM <cmpython@gmail.com> - 2011-07-19 22:10 -0700
    Re: Pythonic way with more than one max possible woooee <woooee@gmail.com> - 2011-07-19 22:37 -0700
    Re: Pythonic way with more than one max possible Chris Rebert <clp2@rebertia.com> - 2011-07-19 23:56 -0700
  Re: Pythonic way with more than one max possible CM <cmpython@gmail.com> - 2011-07-20 13:25 -0700

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